Give the positional isomers of 2 halopropane
(CH3)2CH
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<h3><u>Answer;</u></h3>
Decrease in pressure
<h3><u>Explanation;</u></h3>
- If the pressure of a system is increased, the reaction will shift toward the side with fewer moles of gas, whereas when the pressure of a system is decreased, the reaction will shift toward the side with more moles of gas.
- In this case; <em><u>If the pressure of the system with the above reaction decreases, the reaction will shift to the left. The reactants side has more moles of gas, so the reaction will shift toward the direction of the reactants.</u></em>
1) Balanced equation
C3H8 + 5O2 -> 3 CO2 + 4 H2O
2) 0.700 L C3H8
Given the pressure and temperature do not change, the molar ratio is equivalent to volume ratio
1molC3H8 / 5 mol O2 => 1 L C3H8 / 5 L O2
0.700 L C3H8 / x L O2 = 1 L C3H8 / 5 L O2 => x = 0.700 L C3H8 * 5 L O2 / 1 L C3H8
x = 3.500 L O2
3) CO2 produced
1 L C3H8 / 3 L CO2 = 0.700 L C3H8 / x L CO2 =>
x = 0.700 L C3H8 * 3 L CO2 / 1 L C3H8 = 2.100 L CO2
4) Water vapor produced
1) 1 L C3H8 / 4 L H2O = 0.700 LC3H8 / x L H2O =>
x = 0.700 L C3H8 * 4 L H20 / 1 L C3H8 = 2.800 L H2O