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cestrela7 [59]
3 years ago
6

The volume of a single platinum atom is 1.12×10-23 cm3. what is the volume of a platinum atom in microliters?

Chemistry
2 answers:
Dvinal [7]3 years ago
4 0
Basically, this problem asks you to convert units of volume from cm³ to μL. Cubic centimeters is the cubic volume equivalent of milliliters or mL. According to the metric system for L, microliter is 10⁻⁶ of a liter, while milliliter is 10⁻³ of a liter. Therefore, the solution is written as

(1.12×10⁻²³ cm³)*(1 mL/1 cm³)*(10⁻³ L/ 1 mL)*(1μL/10⁻⁶ L) = 1.12×10⁻²⁰ μL
Ierofanga [76]3 years ago
3 0

<u>Answer:</u> The volume of single platinum atom in micro liters is 1.12\times 10^{-20}\mu L

<u>Explanation:</u>

We are given:

Volume of single platinum atom = 1.12\times 10^{-23}cm^3

To convert this volume into micro liters, we use the conversion factor:

1cm^3=1000\mu L

So, 1.12\times 10^{-23}cm^3\times (\frac{1000\mu L}{1cm^3})=1.12\times 10^{-20}\mu L

Hence, the volume of single platinum atom in micro liters is 1.12\times 10^{-20}\mu L

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Sodium reacts with chlorine gas according to the following reaction: 2Na(s)+Cl2(g)→2NaCl(s) What volume of Cl2 gas, measured at
asambeis [7]

Answer:6.719Litres of Cl2 gas.

Explanation:According to eqn of rxn

2Na +Cl2=2NaCl

P=689torr=689/760=0.91atm

T=39°C+273=312K

according to stoichiometry of the reaction,1Moles of Cl2 gives 2moles of NaCl

But 28g of NaCl was given,we have to convert this to moles by using the relation, n=mass/MW

MW of NaCl=23+35.5=58.5g/mol

n=28g(mass given of NaCl)/58.5

n=0.479moles of NaCl

Going back to the reaction,

if 1moles of Cl2 produces 2moles of NaCl

x moles of Cl2 will give 0.479moles of NaCl.

x=0.479*1/2

x=0.239moles of Cl2.

To find the volume, we use ideal ggas eqn,PV=nRT

V=nRT/P

V=0.239*0.082*312/0.91

V=6.719Litres

6 0
2 years ago
This decomposition is first order with respect to phosphine, and has a half‑life of 35.0 s at 953 K. Calculate the partial press
Solnce55 [7]

Answer:

0.57 atm

Explanation:

When a a reaction is first order, we have from calculus the following relation:

ln[A]t/[A]₀ = - kt

where [A]t is the concentration of A ( phosphine in this case ) after a time, t

           [A]₀ is the initial concentration of A

           k is the rate constant, and

           t is the time

We also know that for a first order reaction

           k = 0.693/ t 1/2

wnere t 1/2 is the half-life.

This equation is derived for the case when A]t/= 1/2 x [A]₀ which occurs at the half-life.

Thus, lets first find k from the half life time, and then solve for t = 70.5 s

k = 0.693 /  35.0 s = 0.0198 s⁻¹

ln [ PH₃ ]t / [ PH₃]₀ = - kt

from the ideal gas law we know pV = nRT, so the volumes cancel:

ln (pPH₃ )t / p(PH₃)₀ = - kt

taking inverse log to both sides of the equation:

(pPH₃ )t / p(PH₃)₀  = - kt

thus:

(pPH₃ )t  = 2.29 atm x e^(- 0.0198 s⁻¹ x 70.5 s ) = 0.57 atm

3 0
3 years ago
A cell in the leaf of a corn plant contains more chloroplasts than a cell in the stem of a corn plant. Based on this observation
Alik [6]

Answer:

This question lacks options, the options are:

A). synthesizes more sugar

B). has a higher chromosome count

C). produces fewer proteins

D). uses less carbon dioxide

The answer is A

Explanation:

The chloroplast is an organelle present in the cells of photosynthetic organisms. It is the site where photosynthesis, which is the production of food (sugars) from sunlight energy, occurs.

According to this question, a cell in the leaf of a corn plant contains more chloroplasts than a cell in the stem of the same corn plant. Based on this observation, it can be inferred that the LEAF CELLS WILL SYNTHESIZE MORE SUGARS THAN THE STEM CELL because the more the chloroplast, the higher the photosynthetic rate and subsequently the higher the amount of sugar produced.

8 0
3 years ago
Plz help me!! Let it be a good amount of presentation.
Svetllana [295]

Answer:

Read the article on Mine Tools called "Active Listening"

Explanation:

Ive used it before for assignments. Its pretty informative and only takes like 10 minutes to read

5 0
2 years ago
If a gas sample has a pressure of 30.7 kpa at 0.00, by how many degrees celsius does the temperature have to increase to cause t
Otrada [13]
Pressure of the gas P1 = 30.7 kpa  
When it doubled P2 = 61.4 kpa  
Temperature T1 = 0 => T1 =. 0 + 273 =273 
Temperature T2 =? 
We have pressure temperature equation P1T1 = P2T2
 => T2 = P1T1 / P2 = (30.7 x 273) / 61.4 = 136.5 
 So the temperature for doubling the pressure is 136.5.
8 0
3 years ago
Read 2 more answers
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