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jarptica [38.1K]
2 years ago
15

3. How many moles of solute are present in a 2300 mL solution of 0.68 M MgSO.?​

Chemistry
1 answer:
Nostrana [21]2 years ago
8 0

There are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated by using the following formula:

molarity = no. of moles / volume

According to this question, a volume of 2300 mL solution is contained in 0.68 M MgSO4. The number of moles is calculated as follows:

no of moles = 0.68M × 2.3

no. of moles = 1.56

Therefore, there are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.

Learn more about moles at: brainly.com/question/12127540

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Molar mass NiSO4 = 154,75 g/m

Mass/ Molar mass = Moles --> 21,6 g / 154,75 g/m = 0,139 moles

These moles are in 100 g of H2O, so we have to make a rule of three to find, the moles in 1000g

100 g _________0,139 moles

1000 g _______ 1,39 moles (molality)

Tº bp solution - 100ºC = 0,512 ºC/molal . 1,39molal . 2

Tº bp solution = (0,512 ºC/molal . 1,39molal . 2) + 100ºC

Tº bp solution = 101,42ºC

4 0
3 years ago
Calculate the molar mass of ammonium chloride
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Note: The combustion of any hydrocarbon produces CO₂ & H₂O. That is,

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The issue remaining is to balance the reaction equation. For these type equation balance Carbon 1st, then Hydrogen and finish with Oxygen. Balancing in this order leaves Oxygen which can be balanced using fractions. If problem requires lowest whole number ratios of elements, simply multiply entire equation by 2 to get standard equation*

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*Standard Equation is defined as the smallest whole number ratios of elements. The 'standard equation' is significant in that it is assumed to be at STP conditions; i.e., 0⁰C (=273K) & 1.0 Atmosphere pressure.

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______________________

**Also, note that water, H₂O(g), is listed as a gas. In some cases it will be listed as a liquid, H₂O(l).

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