3. How many moles of solute are present in a 2300 mL solution of 0.68 M MgSO.?
1 answer:
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Answer:
a) If the reaction has a large negative ΔGo value, the reaction must reach equilibrium at a small extent of reaction value
d) ΔGo and ΔG have the same magnitude, they just have opposite signs.
Explanation:
The fraction of the total heat energy if a system that does useful work is known as Gibb's free energy (G) and the change from the initial to final state is designated by . It is observed that the values of
changes with experimental conditions such as temperature , pressure , concentration etc.
is the standard free energy change which is a balance of two natural tendencies of any system.
- Minimization of potential energy or enthalpic factor
Maximization of disorderliness or entropic factor
Mathematically; =
-
Thus; from above mentioned, the statements that are true about ΔG⁰ and ΔG are:
ΔG⁰ and ΔG can have different values, they don't even have to have the same sign
For a reaction that reaches equilibrium, the minimum value of free energy must be at the equilibrium point
If ΔG⁰ , measured at an extent of reaction = 0.5, is positive, the sign for ΔG when the extent of reaction = 0.80 is also positive.
while the false statements include:
a) If the reaction has a large negative ΔG⁰ value, the reaction must reach equilibrium at a small extent of reaction value
d) ΔG⁰ and ΔG have the same magnitude, they just have opposite signs.
Answer: 26.5 mm Hg
Explanation:
The vapor pressure is determined by Clausius Clapeyron equation:
where,
= initial pressure at
= ?
= final pressure at
= 100 mm Hg
= enthalpy of vaporisation = 28.0 kJ/mol =28000 J/mol
R = gas constant = 8.314 J/mole.K
= initial temperature =
= final temperature =
Now put all the given values in this formula, we get
Thus the vapor pressure of in mmHg at 26.5 ∘C is 26.5