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PilotLPTM [1.2K]
3 years ago
5

What is the pH of a 0.1 M phosphate buffer (pKa = 6.86) that contains equal amounts of acid and conjugate base?

Chemistry
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer : The pH of a 0.1 M phosphate buffer is, 6.86

Explanation : Given,

pK_a=6.86

Concentration of acid = 0.1 M

Concentration of conjugate base (salt) = 0.1 M

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=6.86+\log (\frac{0.1}{0.1})

pH=6.86

Therefore, the pH of a 0.1 M phosphate buffer is, 6.86

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Iron iii chloride ammonium hydroxide balanced equation, complete ionic equation, net ionic equation
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Iron III Chloride has a chemical formula of FeCl₃, while ammonium hydroxide has a chemical formula of NH₄OH. 

The <em>balanced equation</em> would be:

FeCl₃ (aq) + 3 NH₄OH (aq) → Fe(OH)₃ (s) + 3 NH₄Cl (aq)
The precipitate is Fe(OH)₃ or iron iii hydroxide.

To find the <em>complete ionic equation</em>, dissociate the compounds in aqueous phases into their ionic forms:

Fe³⁺ + Cl⁻ + NH₄⁺ + 3 OH⁻ -->  Fe(OH)₃(s) + NH₄⁺ + Cl⁻ 

To find the <em>net ionic equation</em>, cancel out like ions that appear both in the reactant and product side:

Fe³⁺ +  3 OH⁻ -->  Fe(OH)₃


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Hence, there was 450.068g of water in the pot.

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