<span>A. Missing part is ⁴He₂
You can also calculate it by adding/subtracting for atomic mass & atomic numbers
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Answer:
Sodium chloride
Explanation:
There are several salts in seawater, but the most abundant is ordinary table salt or sodium chloride (NaCl). Sodium chloride, like other salts, dissolves in water into its ions, so this is really a question about which ions are present in the greatest concentration. Sodium chloride dissociates into Na+ and Cl- ions.
Answer:
The statements are definitions to chromatography terms which have been highlighted below.
Explanation:
Match the chromatography term with its definition.
Volumetric Flow Rate = The volume of solvent traveling through the column per unit time.
Retention time = The elapsed time between sample injection and detection.
Adjusted Retention Time = The time required by a retained solute to travel through the column beyond the time required by the un -retained solvent.
Linear Flow Rate = The distance traveled by the solvent per unit time.
Retention factor = Describes the amount of time that a sample spends in the stationary phase relative to the mobile phase. It is sometimes also called the capacity factor or capacity ratio.
Relative Volume = Volume of the mobile phase required to elute a solute from the column.
Relative Retention = Ratio of the adjusted retention times or retention factors of two solutes. It is sometimes also called the separation factor.
Partition coefficient = The ratio of the solute concentrations in the mobile and stationary phases.
2.45 °C
From the Ideal gas law (Combined gas law)
PV/T = P'V'/T' .....eq 1
Where:
P - initial pressure
V - initial volume
T - initial temperature
P' - final pressure
V' - final volume
T' - final temperature.
To proceed we have to make T the subject from eq.1
Which is, T = P'V'T/PV.......eq.2
We have been provided with;
Standard temperature and pressure (STP)
P = 760 mm Hg (SP - Standard Pressure)
T = 273.15 K (ST - Standard Temperature)
V = 62.65 L
P' = 612.0 mm Hg
V' = 78.31 L
T' = ? (what we require)
Therefore, we substitute the values into eq.2
T' =
.
T' = 275.60 K
T = (275.60 - 273.15) ......To °C
T = 2.45 °C
>>>>> Answer
Have a nice studies.
