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scoray [572]
3 years ago
12

9. A sports car travels on a straight road at 22.0 km/h and increases its speed to 57.0 km/h in

Physics
1 answer:
Varvara68 [4.7K]3 years ago
6 0

Answer:

4.4 M/s

Explanation:

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The Henry's law constant for CO2 is 3.6 ✕ 10−2 M/atm at 25°C. What pressure (in atm) of carbon dioxide is needed to maintain a C
xeze [42]

To solve this problem we will use Henry's law. This law states that at a constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid. Mathematically it is formulated as follows:

C = K_H*P

Where,

K_H = Henry's constant for C02 at 25°C is equal to 3.6*10^{-2}M/atm

C = Gas concentration is 0.19M

Replacing we have,

0.19 M = (3.6*10^-2 M/atm)*P

P = 5.277 atm

Therefore the pressure of carbon dioxide is 5.277 atm

6 0
3 years ago
Does the response of the light bulb depend on how fast you move the bar magnet? if so, how?
Illusion [34]

Yes , the response of the light bulb depend on how fast you move the bar magnet

Flux is the presence of a force field in a specified physical medium, or the flow of energy through a surface

Lenz's law states that the induced electromotive force with different polarities induces a current whose magnetic field opposes the change in magnetic flux through the loop in order to ensure that the original flux is maintained through the loop when current flows in it.

Yes, waving a magnet around does create an electromagnetic wave which does affect the light bulb .

Due to motion of the bar, there will be a constant change in flux and due to  Lenz's Law a current within the coil will be induced . This induced current can be used to power the light bulb.

As we know that the greater the speed, the greater the magnitude of the current, and the current is zero when there is no motion.

There will be change in brightness as the bar moves with faster speed.

To learn more about Lenz's Law

brainly.com/question/10048453

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7 0
1 year ago
How fast can Usain Bolt run if it takes him 9.9 s to run 100m?​
Arte-miy333 [17]

Answer:

27.8 mph

Explanation:

May I have brainliest please? :)

8 0
3 years ago
Read 2 more answers
To be considered a source of water pollution, the source must include a chemical
forsale [732]

To be considered a source of water pollution, the source must include a chemical is false.

<u>Explanation: </u>

The water pollution may be caused either by chemicals or waste materials that doesn’t contain chemicals such as domestic wastes, organic compounds, heavy metals etc. The life on Earth mostly relies on water and air, and if these two gets polluted; the results will be dangerous.

Around 70% of the planet is covered with water and the present state of its purity is a matter of a serious thought. Looking over various pollutants, only chemical wastes are not responsible to pollute the water.

Instead, there is range of elements from plastic scraps to chemical wastes that comes from either the non-point sources or the point sources. There are organic waste materials, heavy metals, volcanic eruptions, Tsunamis, earthquakes, etc. are also responsible to contaminate water and affect the amphibians as well as humans.

8 0
3 years ago
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Calculate the de Broglie wavelength of: a) A person running across the room (assume 180 kg at 1 m/s) b) A 5.0 MeV proton
solmaris [256]

Answer:

a

\lambda = 3.68 *10^{-36} \  m

b

\lambda_p = 1.28*10^{-14} \ m

Explanation:

From the question we are told that

   The mass of the person is  m =  180 \  kg

    The speed of the person is  v  =  1 \  m/s

    The energy of the proton is  E_ p =  5 MeV = 5 *10^{6} eV  = 5.0 *10^6 * 1.60 *10^{-19} = 8.0 *10^{-13} \  J

Generally the de Broglie wavelength is mathematically represented as

      \lambda = \frac{h}{m * v }

Here  h is the Planck constant with the value

      h = 6.62607015 * 10^{-34} J \cdot s

So  

     \lambda = \frac{6.62607015 * 10^{-34}}{ 180  * 1  }

=> \lambda = 3.68 *10^{-36} \  m

Generally the energy of the proton is mathematically represented as

         E_p =  \frac{1}{2}  *   m_p  *  v^2_p

Here m_p  is the mass of proton with value  m_p  =  1.67 *10^{-27} \  kg

=>     8.0*10^{-13} =  \frac{1}{2}  *   1.67 *10^{-27}  *  v^2

=>   v _p= \sqrt{\frac{8.0 *10^{-13}}{ 0.5 * 1.67 *10^{-27}} }

=>   v = 3.09529 *10^{7} \  m/s

So

        \lambda_p = \frac{h}{m_p * v_p }

so    \lambda_p = \frac{6.62607015 * 10^{-34}}{1.67 *10^{-27} * 3.09529 *10^{7} }

=>     \lambda_p = 1.28*10^{-14} \ m

     

5 0
3 years ago
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