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Alex787 [66]
3 years ago
16

Why might people be able to walk barefoot on hot coals of wood without burning their feet?

Physics
2 answers:
ki77a [65]3 years ago
8 1
Hot coals of wood? Wood is not coals. So they can't burn their feet, there are no hot coals, just wood.
katovenus [111]3 years ago
8 0

The correct answer of this question is : Low thermal conductivity of hot coals.

EXPLANATION :

Before going to answer of this question, first we have to understand the nature of hot coals of wood in terms of conductivity.

The thermal conductivity of the wood is very small i.e it is thermally insulator.

Due to the less thermal conductivity of wood, the heat  partially flows to the foot. The person will feel the heat, but not as much as the heat given by thermal conductors.

Hence, a barefoot person person can walk on hot coals of wood.


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4 0
3 years ago
A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 146 cm and makes an angl
svetlana [45]

Answer:

B = 191.26 cm

θ = -14.73°

Explanation:

given,

magnitude of the first displacement(A) = 146 cm

at an angle of 124°

resultant magnitude = 137 cm

and angle made with x-axis by the resultant(R) = 32.0°

component of A in X and Y direction

A x = A cos θ  = 146 cos 120° = -73 cm

A y = A sin θ = 146 sin 120° = 126.4 cm

now component of resultant in x and y direction

R x = 137 cos 35°

    = 112.2 cm

R y = 137 sin 35°

     = 78.6 cm

resultant is the sum of two vectors

R = A + B

R x = A x + B x

B x =  112.2 - (-73) = 185.2 cm

B y = R y - A y

B y = 78.6 - 126.4 = -47.8 cm

magnitude of B

B = \sqrt{B_x^2+B_y^2}

B = \sqrt{185.2^2+-47.8^2}

B = 191.26 cm

angle\theta = tan^{-1}\dfrac{-47.8}{185.2}

θ = -14.73°

6 0
3 years ago
Hey there!
eimsori [14]

The time taken for the two balls to hit each other is 8 s.

The given parameters:

  • <em>Acceleration of the rocket, a = 2 m/s²</em>
  • <em>Length of the chamber, s = 4 m</em>
  • <em>Speed of the first ball, = V1 = 0.3 m/s</em>
  • <em>Speed of the second ball, V2 = 0.2 m/s</em>

The time taken for the two balls to hit each other is calculated by applying relative velocity formula as shown below;

(V_1 - (-V_2) )t = s\\\\(V_1 + V_2) t = s\\\\(0.3 + 0.2) t = 4\\\\0.5t = 4\\\\t = \frac{4}{0.5} \\\\t = 8 \ s

Thus, the time taken for the two balls to hit each other is 8 s.

Learn more about relative velocity here: brainly.com/question/17228388

8 0
2 years ago
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Which one of the following distances is the shortest?
Kitty [74]
I think the correct answer is C
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3 years ago
near the surface of the earth, objects in free fall (but not terminal velocity) experience a. constant distance. b. constant acc
Alenkasestr [34]
<h3><u>Answer;</u></h3>

B. constant acceleration.

<h3><u>Explanation</u>;</h3>
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  • Therefore,<u> the acceleration of any freely falling object near the surface of the earth is 9.8 m/s².</u>
3 0
4 years ago
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