The body system on the chart
Explanation:
(a) Since, it is given that the blocks are identical so distribution of charge will be uniform on both the blocks.
Hence, final charge on block A will be calculated as follows.
Charge on block A =
= 4.35 nC
Therefore, final charge on the block A is 4.35 nC.
(b) As it is given that the positive charge is coming on block A
. This means that movement of electrons will be from A to B.
Thus, we can conclude that while the blocks were in contact with each other then electrons will flow from A to B.
<span> </span>For any prism-shaped geometry, the volume
(V) is assumed by the product of cross-sectional area (A) and height (h).
<span> V = Ah </span>
<span>
Distinguishing with respect to time gives the
relationship between the rates.
dV/dt = A*dh/dt</span>
<span> in the meantime the area is not altering </span>
<span>
dV/dt = π*(1 ft)^2*(-0.5 ft/min) </span>
<span>
dV/dt = -π/2 ft^3/min ≈ -1.571 ft^3/min
Water is draining from the tank at the rate of π/2
ft^3/min.</span>
Answer:

Explanation:
The time lag between the arrival of transverse waves and the arrival of the longitudinal waves is defined as:

Here d is the distance at which the earthquake take place and
is the velocity of the transverse waves and longitudinal waves respectively. Solving for d:

The acceleration of the box up the ramp is 9.65 m/s².
<h3>
What is the magnitude of acceleration of the box?</h3>
The magnitude of the acceleration of the box is calculated by applying Newton's second law of motion as shown below;
F(net) = ma
where;
- m is the mass of the box
- a is the acceleration of the box
The net force on the box is calculated as follows;
F(net) = F - Ff
F(net) = F - μmgcosθ
where;
- θ is the inclination of the plane
- μ is coefficient of friction
F(net) = 170 - (0.3 x 15 x 9.8 x cos55)
F(net) = 144.7
The acceleration of the box is calculated as;
a = F(net) / m
a = (144.7) / (15)
a = 9.65 m/s²
Thus, the acceleration of the box up the ramp is 9.65 m/s².
Learn more about acceleration here: brainly.com/question/14344386
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