a block of mass 5 kg is being pulled along a board horizontally with a constant velocity; the coefficient of friction between th
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For Newton's second law, the force is equal to the product between the mass and the acceleration of the rocket:
From which we can rewrite the acceleration as
where m=7.0 kg.
The velocity of the rocket is the derivative of the acceleration:
and if we substitute x=9.0 m, we find the rocket velocity after 9.0 m:
From which we can rewrite the acceleration as
where m=7.0 kg.
The velocity of the rocket is the derivative of the acceleration:
and if we substitute x=9.0 m, we find the rocket velocity after 9.0 m:
Answer:
<em>The end of the ramp is 38.416 m high</em>
Explanation:
<u>Horizontal Motion </u>
When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.
The maximum horizontal distance traveled by the object can be calculated as follows:
If the maximum horizontal distance is known, we can solve the above equation for h:
The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:
h= 38.416 m
The end of the ramp is 38.416 m high