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Serjik [45]
3 years ago
12

a block of mass 5 kg is being pulled along a board horizontally with a constant velocity; the coefficient of friction between th

e two surface is 0.25, then what is the frictional forces that opposes the motion​
Physics
1 answer:
antoniya [11.8K]3 years ago
6 0

The block is in equilibrium, so the net forces parallel and perpendicular to the surface are

∑ F[para] = F[normal] - mg = 0

∑ F[perp] = F[pull] - F[friction] = 0

where mg is the weight of the block. It follows that

F[normal] = mg = (5 kg) (9.8 m/s²) = 49 N

and so the frictional force has magnitude

F[friction] = 0.25 F[normal] = 12.25 N ≈ 12 N

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Equal amounts of heat are added to equal masses of ice and copper at the same initial temperature. Which substance will have the
pychu [463]

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Figure a shows a copper-colored cylinder of mass m and temperature change delta T. The heat Q, shown as a wavy rightward horizontal arrow, is transferred to the cylinder from the left. To the right of this image is a similar image, except that the heat transferred Q prime is twice the heat Q. The temperature change of this second cylinder, which is also labeled m, is two delta T. This cylinder is surrounded by small black wavy lines radiating outward. Figure b shows the same two cylinders as in Figure a. The left cylinder is labeled m and delta T and has a wavy heat arrow pointing at it from the left that is labeled Q. The right cylinder is labeled two m and delta T and has a wavy heat arrow pointing to it from the left labeled Q prime equals two Q. Figure c shows the same copper cylinder of mass m and with temperature change delta T, with heat Q being transferred to it. To the right of this cylinder, Q prime equals ten point eight times Q is being transferred to another cylinder filled with water whose mass and change in temperature are the same as that of the copper cylinder.

7 0
3 years ago
A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point
Nonamiya [84]

Answer:

1.52 m

Explanation:

We are given that

Maximum force=F=679 N

Mass of rock ,m=385 kg

Distance,d=0.233 m

We have to find the  minimum total length L of the rod required to move the rock.

Torque on rock=T_1=mgd=385\times 9.8\times 0.233=879.11 N

Where g=9.8m/s^2

Torque on man=T_2=Force\times distance=(L-d)\times 679=(L-0.233)\times 679

T_1=T_2

(L-0.233)\times 679=879.11

L-0.233=\frac{879.11}{679}=1.29

L=1.29+0.233=1.523\approx 1.52 m

Hence, the minimum total  length of rod=1.52 m

3 0
3 years ago
Describe at least two ways that you can reduce the friction between two solid surfaces
Firlakuza [10]
I will try to name as much as I can :

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• Using a spherical object leaves the surface with very little surface area, basically using balls will help alot
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8 0
4 years ago
Which type of wave interaction is shown in the photo?
julia-pushkina [17]

The wave interaction that is shown in the photo is refraction as light moves from air to water.

<h3>What is refraction?</h3>

Refraction refers to the change in the frequency of a wave and the direction of the wave as it moves from one medium to another. We know that waves makes a body under water to look slightly different than when it is in air.

Thus, the wave interaction that is shown in the photo is refraction as light moves from air to water.

Learn more about refraction:brainly.com/question/14760207

#SPJ1

7 0
2 years ago
(BRAINLIEST)
UkoKoshka [18]

Answer:

Gravity

because it's factorised by mass of a body.

For other forces, they deal with charges of negligible mass and weights

4 0
4 years ago
Read 2 more answers
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