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anygoal [31]
3 years ago
6

The energy of a photon is E=\frac{hc}{\lambda}E = h c λ where c is the speed of light and h is a constant known as Planck's cons

tant. If a red photon has twice the wavelength of a violet photon, then the energy of the red photon is the energy of the violet photon. This shows that short-wavelength photons carry proportionally energy than long-wavelength photons.
Physics
1 answer:
Basile [38]3 years ago
5 0

Answer: As a red photon has a twice of the wavelegth to the violet photon then the red photon has half energy of the violet photon.

Explanation: In order to explain the above statement we have to consider the Plack postulate where the energy of photons depend directely of the frequency . As the wavelength and frequency are related by :

c= λ*υ c is the speed of light,  λ is the wavelength and υ the frequency of the photon

so the energy of  photons are inversely proportional to the wavelength.

As a consequence twice wavelengtht means half energy for the photon.  

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A charge of 25 nC is uniformly distributed along a straight rod of length 3.0 m that is bent into a circular arc with a radius o
Greeley [361]

Answer:

E = 31.329 N/C.

Explanation:

The differential electric field dE at the center of curvature of the arc is

dE = k\dfrac{dQ}{r^2}cos(\theta ) <em>(we have a cosine because vertical components cancel, leaving only horizontal cosine components of E. )</em>

where r is the radius of curvature.

Now

dQ = \lambda rd\theta,

where \lambda is the charge per unit length, and it has the value

\lambda = \dfrac{25*10^{-9}C}{3.0m} = 8.3*10^{-9}C/m.

Thus, the electric field at the center of the curvature of the arc is:

E = \int_{\theta_1}^{\theta_2} k\dfrac{\lambda rd\theta  }{r^2} cos(\theta)

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2}cos(\theta) d\theta.

Now, we find \theta_1 and \theta_2. To do this we ask ourselves what fraction is the arc length  3.0 of the circumference of the circle:

fraction = \dfrac{3.0m}{2\pi (2.3m)}  = 0.2076

and this is  

0.2076*2\pi =1.304 radians.

Therefore,

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2} cos(\theta)d\theta= \dfrac{\lambda k}{r} \int_{0}^{1.304}cos(\theta) d\theta.

evaluating the integral, and putting in the numerical values  we get:

E = \dfrac{8.3*10^{-9} *9*10^9}{2.3} *(sin(1.304)-sin(0))\\

\boxed{ E = 31.329N/C.}

4 0
3 years ago
A chemical equation lists NaHCO3(s) as a reactant. What does (s) indicate?
Ostrovityanka [42]

Answer:

The (s) indicates that the state of matter for NaHCO3 is solid.

Explanation:

When a chemical reaction is written, the state of matter for each components of the reactants and products are mentioned in brackets along with their names or formulas.

For example, NaHCO3 has (s) mentioned in the brackets. The s shows that the state of matter for NaHCO3. (l) represents liquid format. (g) represents that the state of matter is gas.

5 0
3 years ago
Read 2 more answers
What is the equation used to calculate the total amount of energy used by an appliance?
charle [14.2K]

Answer:

Power = Current × Voltage

Explanation:

Units:

Power = Watts

Current = Àmperes

Voltage = Volts

8 0
3 years ago
What is the name of the hair-like structures on sponge cells that move back and forth to help move water, nutrients, and waste t
Dima020 [189]
I think it's B. Flagella

5 0
3 years ago
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A solid cube of side 5cm has a mass of 250g. What is its density in kgm ??​
Mariulka [41]

Answer:

5kgm

Explanation:

convert cm to m and g to kg

250/1000=0.25kg

5/1000=0.05m

then find the density

density=mass/volume

=0.25kg/0.05m

=5kgm

7 0
3 years ago
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