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Kipish [7]
3 years ago
7

Describe, in detail, an experiment in which you could determine the power for a period of several hours. You must be able to tel

l how to measure the force and the distance to calculate work or your example will not be accepted.
Physics
2 answers:
Ad libitum [116K]3 years ago
6 0

Answer:

Lets say, we have a car with a specific mass, m and is forced to move in given direction starting from its initial point "A", to a final position "B". The force,F which makes it move in that direction is about 10 N in total. While, the distance,D covered between the two given points is about 5 meters. So, now we can calculate the work,W done by the car in a given direction inside that specific area. So, we have to place all the values inside the equation mentioned below,

  • <u>W=F.D,</u>

So, after placing the required data into the equation, we will get the following results:

W=(10)*(5),

  • <u>W=50 joules(J).</u>

However, to find out the power dissipation,P for a system which runs on a given scale of time,t as the current,I and the potential difference or voltage,V is all involved to find out the total power dissipation inside the circuit or any system that is under consideration. Lets, say we have circuit in which a charge of 6 coulombs(C) passes through a wire of certain length,L. And that the given time is about 2 seconds(sec). The voltage,V provided to the circuit is about 7 volts(V), so how can we be able to find the amount of power dissipation inside the circuit.

So, for that reason we have the following equation, which is given as follows:

<u>P=I.V,</u>

And we can also evaluate the equation much further, as follows:

P=(Q/t).(v), ∴I=Q/t,

So, we can have the required results that we desire by placing the data inside the equation:

P= (6/2)*(7),

P=3*7,

  • <u>Power= 21 Watts.</u>

sashaice [31]3 years ago
5 0

Answer:

Explanation:

Fill up the tank of water which is at a height.

So Work Done = Change n Potential Energy = mgh

Here h is the Height of the Center of mass of the water

Divide it by Time to get power

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In an RC circuit, what fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for
4vir4ik [10]

Answer:

The  fraction fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for 3.0 time constants is  

      k  = 0.903

Explanation:

From the question we are told that

     The time  constant  \tau  =  3

The potential across the capacitor can be mathematically represented as

     V  =  V_o  (1 -  e^{- \tau})

Where V_o is the voltage of the capacitor when it is fully charged

    So   at  \tau  =  3

     V  =  V_o  (1 -  e^{- 3})

     V  =  0.950213 V_o

   Generally energy stored in a capacitor is mathematically represented as

             E = \frac{1}{2 } * C  * V ^2

In this equation the energy stored is directly proportional to the the square of the potential across the capacitor

Now  since capacitance is  constant  at  \tau  =  3

        The  energy stored can be evaluated at as

         V^2 =  (0.950213 V_o )^2

       V^2 =  0.903  V_o ^2

Hence the fraction of the energy stored in an initially uncharged capacitor is  

      k  = 0.903

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A 98 N ball is suspended from a cable so that it hangs 3.5 m above the earth. Find the mass of the ball and the
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Answer:

Yes

Explanation:

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Explain what happens to light when it is refracted at the surface of water.
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Light will make the object appear “broken” or in an irregular shape.

Refraction is the change in direction of waves.
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A block rests on a frictionless horizontal surface and is attached to a spring. When set into simple harmonic motion, the block
MariettaO [177]

Answer:

v₀ = 0.5058 m/s

Explanation:

From the question, for the block to hit the bottle, the elastic potential energy of the spring at the bottle (x = 0.08 m) should be equal to the sum of the elastic potential energy of the spring at x = 0.05 m and the kinetic energy of block at x = 0.05 m

Now, the potential energy of the block at x = 0.08 m is ½kx²

where;

k is the spring constant given by; k = ω²m

ω is the angular velocity of the oscillation

m is the mass of the block.

Thus, potential energy of the spring at the bottle(x = 0.08 m) is;

U = ½ω²m(0.08m)²

Also, potential energy of the spring at the bottle(x = 0.05 m) is;

U = ½ω²m(0.05m)²

and the kinetic energy of the block at x = 0.05 m is;

K = ½mv₀²

Thus;

½ω²m(0.08)² = ½ω²m(0.05)² + ½mv₀²

Inspecting this, ½m will cancel out to give;

ω²(0.08)² = ω²(0.05)² + v₀²

Making v₀ the subject, we have;

v₀ = ω√((0.08)² - (0.05)²)

So,

v₀ = 8.1√((0.08)² - (0.05)²)

v₀ = 0.5058 m/s

7 0
3 years ago
When objects exchange charge, why do we say it's the negative charge that moves and not the positive?
Novay_Z [31]

Answer:

It is said that the negative charge moves because the electrons in the atoms of any object are taken or given to the atoms of another object.

Explanation:

The atom is made up of protons, electrons and neutrons. The number of protons is exactly the same to the number of electrons for a certain element. For example, hydrogen: it has a proton, and therefore, an electron.

The electron has a negative charge. The proton has a positive charge. And the neutron has no charge, so it is neutral. While the atom has the same number of protons and electrons, it will not be electrically charged.

An example of how a charge exchange occurs between two objects is through the case of rubbing. This makes the atoms of the two objects close enough that there is an electron transfer, causing any of the objects to gain or lose electrons as a consequence of each other interaction. In the case of transferring electrons, the atom will have a greater number of protons, so it will be positively charged. When the atom receive electrons, it will have a greater number of electrons, so it will be negatively charged.

Therefore, since it is the electrons that move from one atom to another, then it is the negative charge that moves (<em>characterized by the electrons</em>) and not the positive charge (<em>characterized by the protons</em>).

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