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Kipish [7]
3 years ago
7

Describe, in detail, an experiment in which you could determine the power for a period of several hours. You must be able to tel

l how to measure the force and the distance to calculate work or your example will not be accepted.
Physics
2 answers:
Ad libitum [116K]3 years ago
6 0

Answer:

Lets say, we have a car with a specific mass, m and is forced to move in given direction starting from its initial point "A", to a final position "B". The force,F which makes it move in that direction is about 10 N in total. While, the distance,D covered between the two given points is about 5 meters. So, now we can calculate the work,W done by the car in a given direction inside that specific area. So, we have to place all the values inside the equation mentioned below,

  • <u>W=F.D,</u>

So, after placing the required data into the equation, we will get the following results:

W=(10)*(5),

  • <u>W=50 joules(J).</u>

However, to find out the power dissipation,P for a system which runs on a given scale of time,t as the current,I and the potential difference or voltage,V is all involved to find out the total power dissipation inside the circuit or any system that is under consideration. Lets, say we have circuit in which a charge of 6 coulombs(C) passes through a wire of certain length,L. And that the given time is about 2 seconds(sec). The voltage,V provided to the circuit is about 7 volts(V), so how can we be able to find the amount of power dissipation inside the circuit.

So, for that reason we have the following equation, which is given as follows:

<u>P=I.V,</u>

And we can also evaluate the equation much further, as follows:

P=(Q/t).(v), ∴I=Q/t,

So, we can have the required results that we desire by placing the data inside the equation:

P= (6/2)*(7),

P=3*7,

  • <u>Power= 21 Watts.</u>

sashaice [31]3 years ago
5 0

Answer:

Explanation:

Fill up the tank of water which is at a height.

So Work Done = Change n Potential Energy = mgh

Here h is the Height of the Center of mass of the water

Divide it by Time to get power

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Astronauts are trained for take-off in a high-speed centrifuge of 4.7 m radius that spins in the horizontal plane.
Leokris [45]

Answer:

a) 1.94 \frac{rad}{s}

b) 9.12\frac{m}{s}

c) Towards the center of the centrifuge

Explanation:

a)

Becuse the centrifuge rotates in circular motion, there's an angular acceleration tha simulates high gravity accelerations

a_{rad}=\omega r^{2}

with r the radius and ω the amgular velocity, in or case a_rad=3.5g so:

3.5g=\omega r^{2} and g=9.8\frac{m}{s^{2}}

solving for ω:

\omega=\frac{3.5g}{r^2}=\frac{3.5*9.8}{4.2^2}

\omega = 1.94 \frac{rad}{s}

b) Linear speed (v) and angular speed are related by:

v=\omega r =(1.94)(4.7)

v= 9.12\frac{m}{s}

c) The apparent weigth is pointing towards the center of the circle, becuse angular acceleration is pointing in that direction.

8 0
3 years ago
What is the kinetic energy of an object with a mass of 50kg and is and it is traveling at a rate of 60m/s.
liq [111]

Answer:

90,000 J

Explanation:

Kinetic energy can be found using the following formula.

KE=\frac{1}{2}mv^2

where <em>m </em>is the mass in kilograms and <em>v</em> is the velocity in m/s.

We know the object has a mass of 50 kilograms. We also know it is a traveling at a rate of 60 m/s. Velocity is the speed of something, so the velocity of the object is 60 m/s.

<em>m</em>=50

<em>v</em>=60

Substitute these values into the formula.

KE=\frac{1}{2}*50*60^2

First, evaluate the exponent: 60^2. 60^2 is the same as multiplying 60, 2 times.

60^2=60*60=3,600

KE=\frac{1}{2}*50*3,600

Multiply 50 and 3,600

KE=\frac{1}{2}*180,000

Multiply 1/2 and 3,600, or divide 3,600 by 2.

KE=90,000

Add appropriate units. Kinetic energy uses Joules, or J.

KE=90,000 Joules

The kinetic energy of the object is 90,000 Joules

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Answer:

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Answer:

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