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Kipish [7]
3 years ago
7

Describe, in detail, an experiment in which you could determine the power for a period of several hours. You must be able to tel

l how to measure the force and the distance to calculate work or your example will not be accepted.
Physics
2 answers:
Ad libitum [116K]3 years ago
6 0

Answer:

Lets say, we have a car with a specific mass, m and is forced to move in given direction starting from its initial point "A", to a final position "B". The force,F which makes it move in that direction is about 10 N in total. While, the distance,D covered between the two given points is about 5 meters. So, now we can calculate the work,W done by the car in a given direction inside that specific area. So, we have to place all the values inside the equation mentioned below,

  • <u>W=F.D,</u>

So, after placing the required data into the equation, we will get the following results:

W=(10)*(5),

  • <u>W=50 joules(J).</u>

However, to find out the power dissipation,P for a system which runs on a given scale of time,t as the current,I and the potential difference or voltage,V is all involved to find out the total power dissipation inside the circuit or any system that is under consideration. Lets, say we have circuit in which a charge of 6 coulombs(C) passes through a wire of certain length,L. And that the given time is about 2 seconds(sec). The voltage,V provided to the circuit is about 7 volts(V), so how can we be able to find the amount of power dissipation inside the circuit.

So, for that reason we have the following equation, which is given as follows:

<u>P=I.V,</u>

And we can also evaluate the equation much further, as follows:

P=(Q/t).(v), ∴I=Q/t,

So, we can have the required results that we desire by placing the data inside the equation:

P= (6/2)*(7),

P=3*7,

  • <u>Power= 21 Watts.</u>

sashaice [31]3 years ago
5 0

Answer:

Explanation:

Fill up the tank of water which is at a height.

So Work Done = Change n Potential Energy = mgh

Here h is the Height of the Center of mass of the water

Divide it by Time to get power

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Verizon [17]

Answer:

skateboard b

Explanation:

p=mv

skateboard a

p=(60kg)(1.5m/s)=90kg*m/s

skateboard b

p=(50kg)(2m/s)=100kg*m/s

5 0
2 years ago
The time required to produce one cycle of a wave is known as the waves
eimsori [14]
The time described above is known as the waves Period.
The time which it takes for a particle to complete one full cycle is known as the period. Period is normally measured in seconds. Frequency on the other hand is the number of cycles which are completed in a given period of time e.g a second. periodic time T is given by reciprocal of frequency (1/f).
6 0
3 years ago
an athlete whirls an 8.71 kg hammer tied to the end of a 1.5 m chain in a simple horizontal circle where you should ignore any v
-BARSIC- [3]

Answer:

T = 692.42 N

Explanation:

Given that,

Mass of hammer, m = 8.71 kg

Length of the chain to which an athlete whirls the hammer, r = 1.5 m

The angular sped of the hammer, \omega=1.16\ rev/s=7.28\ rad/s

We need to find the tension in the chain. The tension acting in the chain is balanced by the required centripetal force. It is given by the formula as follows :

F=m\omega^2r\\\\=8.71\times (7.28)^2\times 1.5\\\\=692.42\ N

So, the tension in the chain is 692.42 N.

5 0
2 years ago
A sand mover at a quarry lifts 2,000 kg of sand per minute a vertical distance of 12 m. The sand is initially at rest and is dis
Marianna [84]

Answer:

<h2>E. 3.95kW</h2>

Explanation:

Power is defined as the rate of workdone.

Power = Workdone/time taken

Given Workdone = Force * distance

Power = Force * distance/time taken

Power = mgd/t (F = mg)

m = mass of the sand in kg

g = acceleration due to gravity in m/s²

d = vertical distance covered in metres

t = time taken in seconds

Given m = 2000kg, d = 12m, t = 1min = 60secs, g = 9.8m/s²

Power = 2000*9.8*12/60

Power = 3920Watts

Minimum rate of power that must be supplied to this machine is 3920Watts or 3.92kW

5 0
3 years ago
A block is resting on a platform that is rotating at an angular speed of 2.4 rad/s. The coefficient of static friction between t
Sloan [31]

Answer:

r = 0m is the Minimum distance from the axis at which the block can remain in place wothout skidding.

Explanation:

From a sum of forces:

Ff = m*a   where Ff = μ * N    and a = \frac{V^2}{r}=\omega^2*r

N - m*g = 0   So, N = m*g.   Replacing everything on the original equation:

\mu*m*g = m*\omega^2*r   (eq2)

Solving for r:

r = \frac{\mu*g}{\omega^2}=1.41m

If we analyze eq2 you can conclude that as r grows, the friction has to grow (assuming that ω is constant), so the smallest distance would be 0 and the greatest 1.41m. Beyond that distance, μ has to be greater than 0.83.

4 0
2 years ago
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