<span>As new discoveries are made, existing theories are revised or replaced.</span>
V=abc
a = 2,3cm
b=12,2mm = 1,22cm
c = 0,75inch = 1,905cm
V = 2,3cm*1,22cm*1,905cm ≈ 5,35cm³
Answer:
392.97 litres
Explanation:
From the equation of reaction, we can see that 1 mole of methane yielded 1 mole of carbon iv oxide. Hence, 15.9 moles of methane will yield 15.9 moles of carbon iv oxide.
At s.t.p one mole of a gas occupies a volume of 22.4L ,hence 15.9 moles of a gas will occupy a volume of 22.4 × 15.9 which equals
356.16L.
Now, we can use the general gas equation to get the volume produced at the values given.
We have the following values;
V1 = 356.16L P1= 1 atm ( standard pressure) T1 = 273K ( standard temperature) V2 = ? T2 = 23.7 + 273 = 296.7K P2 = 0.985 atm
The general form of the general gas equation is given as :
(P1V1)T1 = (P2V2)/T2
After substituting the values , we get V2 to be 392.97Litres
Answer:
(a) Potassium 3; phosphorus 1; oxygen 4
(b) Aluminium 3; oxygen 9; hydrogen 9
(c) Iron 10; sulfur 15; oxygen 60
Explanation:
(a) K₃PO₄
In one formula unit of K₃PO₄ , there are three atoms of potassium (K), one atom of phosphorus (P), and four atoms of oxygen (O).
In two formula units there are
Potassium — six atoms
Phosphorus — two atoms
Oxygen — eight atoms
(b) Al(OH)₃
In one formula unit of Al(OH)₃, there is one atom of aluminium (Al), three atoms of O, and three atoms of Hydrogen (H).
In three formula units there are
Aluminium — three atoms
Oxygen — nine atoms
Hydrogen — nine atoms
(c) Fe₂(SO₄)₃
In one formula unit of Fe₂(SO₄)₃, there are two atoms of iron (Fe), three atoms of sulfur (S), and 12 atoms of O.
In five formula units there are
Iron — 10 atoms
Sulfur — 15 atoms
Oxygen — 60 atoms
