<span>The answer is H2CO itcontains both sigma and pi bonds.</span>
When the magnitude of the charge Q = I*T
when we have I current = 2.3
and T = 35 min * 60 = 2100 s
by substitution:
∴ Q = 2.3 * 2100
= 4830 C
according to this reaction equation:
Cu2+ + 2e- → Cu
we can see that 1 mol Cu2+ need 2 mol e- to produce Cu
mol of electron e- = Q / faraday's constant
= 4830 / 96485
= 0.05 mol
when 1 mol Cu2+ → 2 mol e-
?? ← 0.05 mol
∴ moles Cu2+ = 0.05 /2 = 0.025 mol
∴ mass Cu2+ = moles Cu2+ * molar mass Cu2+
= 0.025 * 64
= 1.6 g
Answer:
Because both carbon and oxygen are demanded to obey the octet's rule.
Explanation:
Hello.
In this case, recalling the Lewis dot structure of CO₂ which is basically:

We know oxygen has six valance electron whereas carbon four valence electrons, it means that oxygen needs two electrons in order to attain eight electrons and carbon needs four electrons for the same purpose. In such a way, as carbon dioxide contains one carbon atom and two oxygen atoms we infer that each oxygen is providing two electrons for a total of four to allow the carbon obey the octet as well as oxygen and this is attained via two double bonds.
Best regards.
Carbon needs four more valence electrons, or a total of eight valence electrons, to fill its outer energy level.