The correct answer is (B)
Which is (kQ1Q2) / d^2
Answer:
3. Is 180◦ out of phase with the original wave at the end.
Explanation:
Here when wave is reflected by the rigid boundary then due to the rigidly bounded particles at the end or boundary they have tendency not to move and remains fixed at their position.
Due to this fixed position we can say when wave reach at that end the particles will not move and they apply equal and opposite force at the particles of string
Due to this the reflected wave is transferred back into the string in opposite phase with respect to the initial wave
so here correct answer will be
3. Is 180◦ out of phase with the original wave at the end.
Answer:
0.1 L
Explanation:
From the question given above, we obtained the following data:
Initial volume (V₁) = 0.05 L
Initial Pressure (P₁) = 207 KPa
Final pressure (P₂) = 101 KPa
Final volume (V₂) =?
We can obtain the new volume (i.e the final volume) of the gas by using the Boyle's law equation as illustrated below:
P₁V₁ = P₂V₂
207 × 0.05 = 101 × V₂
10.35 = 101 × V₂
Divide both side by 101
V₂ = 10.35 / 101
V₂ = 0.1 L
Thus, the new volume of the gas is 0.1 L
Answer:
Peak current= 84.86 A
Area of each turn = 0.029 m^2
Explanation:
The peak value of current can be obtained from Irms= 0.707Io. Where Io is the peak current.
Hence;
Irms= 60.0A
Io= Irms/0.707
Io = 60.0/0.707
Io= 84.86 A
Vrms= 0.707Vo
Vo= Vrms/0.707= 170/0.707 = 240.45 V
From;
V0 = NABω
Where;
Vo= peak voltage
N= number of turns
B= magnetic field
A= area of each coil
ω= angular velocity
But ω= 2πf = 2×π×95= 596.9 rads-1
Substituting values;
A= Vo/NBω
A= 240.45/550×0.025×596.9
A= 0.029 m^2
Answer:
1404 N .
Explanation:
Force = rate of change of momentum
d/dt ( mv₁ - mv₂ )
If v₂ = - v₁
rate of change of momentum
= d/dt ( mv₁+mv₁ )
=2x v₁ dm / dt ( Here velocity of water v₁ throughout is constant )
Force = 2 xv₁ dm / dt
Given ,
v₁ = 18 m/s
dm / dt = rate of flow of mass of water
= 39 kg / s
Putting the values in the equation above
Force = 2xv₁ dm / dt
= 2x18 x 39
= 1404 N .
