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Whitepunk [10]
3 years ago
7

What three categories can every living thing in a forest ecosystem be sorted into

Physics
1 answer:
juin [17]3 years ago
4 0

Answer:

Producers

Consumers

Decomposers

Explanation:

The three categories in which every living thing in a forest ecosystem can be sorted into are producers, consumers and decomposers.

The producers as the name implies manufactures food for the whole of the ecosystem. They take inorganic materials from the environment and convert them into useful food materials. All plants are producers and some micro-organisms.

Animals are consumers and they take up the produced food for their own nourishment and life activities.

Decomposers recycles materials in the ecosystem by converting wastes generated by producers and consumers into useful products that returns to the atmosphere or replenishes soil nutrients.

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Cat walks 100 m  East, then turns around and walks 25 m west. What is the cats displacement?
kvasek [131]

Answer:

<h3>75m</h3>

Explanation:

If a cat walk 100m East, this means that it is walking in the positive x direction, the distance will therefore be +100m

If it turns around and walks 25 m west, the direction of movement is in the negative x direction i.e -25m

Taking the sum;

Displacement = +100m - 25m

Displacement of the cat = 75m

hence the cats displacement is 75m

8 0
3 years ago
Help me please my teacher requires work!!
emmainna [20.7K]
The change needed is from 8 to 28, a change of 20 m/s. At a rate of 2m/s/s it will take 10 seconds for it to happen (2x10=20). I hope this helps.
8 0
3 years ago
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Dmitry [639]

Answer:

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Explanation:

3 0
3 years ago
Each of 134 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first bl
poizon [28]

Answer:

A. T=126N

B. T=63N

Explanation:

To determine the tension in each given blocks, we first determine the acceleration of each block. It obvious that each mass will move with the same acceleration since the string connecting them is massless.

Hence using the equation of force we have

F=ma

Where m=total mass of blocks,

a=acceleration

F= force applied in this case the tension in the string.

For a 134 identical masses with an applied force of 134N, the acceleration of each mass can be computed as

134=134m*a

a=134/134m

a=(1/m )m/s²

a. To calculate the tension in the string between the 126 and 127 block, we use the equation below

T=ma

Since the number of blocks before the string is 126, we multiply the mass of each block by 126.

Hence the tension can be computed as

T=126m*a

Since a=1/m then

T=126m*1/m

T=126N

B.To calculate the tension in the string between the 63 and 64 block, we use the equation below

T=ma

Since the number of blocks before the string is 63, we multiply the mass of each block by 63.

Hence the tension can be computed as

T=63m*a

Since a=1/m then

T=63m*1/m

T=63N

8 0
4 years ago
Suppose a car traveled 120 miles in two hours. What can we conclude about the car based on the mean value theorem.
Lapatulllka [165]
We can conclude that it is traveling at a constant rate of 60 miles per hour
120mi/2hrs
= 60
4 0
2 years ago
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