Answer:
<h3>75m</h3>
Explanation:
If a cat walk 100m East, this means that it is walking in the positive x direction, the distance will therefore be +100m
If it turns around and walks 25 m west, the direction of movement is in the negative x direction i.e -25m
Taking the sum;
Displacement = +100m - 25m
Displacement of the cat = 75m
hence the cats displacement is 75m
The change needed is from 8 to 28, a change of 20 m/s. At a rate of 2m/s/s it will take 10 seconds for it to happen (2x10=20). I hope this helps.
Answer:
A. T=126N
B. T=63N
Explanation:
To determine the tension in each given blocks, we first determine the acceleration of each block. It obvious that each mass will move with the same acceleration since the string connecting them is massless.
Hence using the equation of force we have
F=ma
Where m=total mass of blocks,
a=acceleration
F= force applied in this case the tension in the string.
For a 134 identical masses with an applied force of 134N, the acceleration of each mass can be computed as
134=134m*a
a=134/134m
a=(1/m )m/s²
a. To calculate the tension in the string between the 126 and 127 block, we use the equation below
T=ma
Since the number of blocks before the string is 126, we multiply the mass of each block by 126.
Hence the tension can be computed as
T=126m*a
Since a=1/m then
T=126m*1/m
T=126N
B.To calculate the tension in the string between the 63 and 64 block, we use the equation below
T=ma
Since the number of blocks before the string is 63, we multiply the mass of each block by 63.
Hence the tension can be computed as
T=63m*a
Since a=1/m then
T=63m*1/m
T=63N
We can conclude that it is traveling at a constant rate of 60 miles per hour
120mi/2hrs
= 60