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Whitepunk [10]
4 years ago
7

What three categories can every living thing in a forest ecosystem be sorted into

Physics
1 answer:
juin [17]4 years ago
4 0

Answer:

Producers

Consumers

Decomposers

Explanation:

The three categories in which every living thing in a forest ecosystem can be sorted into are producers, consumers and decomposers.

The producers as the name implies manufactures food for the whole of the ecosystem. They take inorganic materials from the environment and convert them into useful food materials. All plants are producers and some micro-organisms.

Animals are consumers and they take up the produced food for their own nourishment and life activities.

Decomposers recycles materials in the ecosystem by converting wastes generated by producers and consumers into useful products that returns to the atmosphere or replenishes soil nutrients.

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Which is not a unit of heat? joule British Thermal Unit calorie kelvin
insens350 [35]
The Joule, the BTU, and the calorie are units of energy,
in the form of heat or in any other form.

The Kelvin is a unit of temperature.
8 0
3 years ago
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An object moves along the grid through the points A, B, C, D, E, and Fas shown below.
sveticcg [70]

Answer:

Total distance = 6.5 km

Explanation:

Let the distance be denoted by the vectors drawn from A, B, C, D, E, and F.

Then the distance covered can be calculated by adding the vectors in the direction given.

Total distance = 3km + 1km+ 1.5km+ 0.5km+ 0.5km

Total distance = 6.5 km

If we were to find the displacement ( shortest distance) then the head to tail rule would be applied using the vectors.

7 0
3 years ago
1.A motorcycle’s velocity at the top of the hill is 11.0 m/s. 4.0 seconds later it reaches the bottom of the hill with a velocit
daser333 [38]

Answer:

1) as far as I remember

Let's take 20 as vf (final velocity) and 11 as (initial velocity) and 4 as time

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Asnwer 2.25

6 0
3 years ago
Which disease is caused by the loss of bone calcium?
Lelechka [254]

rickets is right answer

3 0
3 years ago
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Calculate the change internal energy (δe) for a system that is giving off 45.0 kj of heat and is performing 855 j of work on th
adelina 88 [10]
The change in internal energy of a system is given by (second law of thermodynamics)
\Delta U = Q + W
where Q is the heat absorbed by the system and W is the work done on the system.

In order to correctly evaluate the internal energy change, we must be careful with the signs of Q and W:
Q positive -> Q absorbed by the system
Q negative -> Q released by the system
W positive -> W done on the system by the surroundings
W negative -> W done by the system on the surroundings

In our problem, the heat released by the system is Q=-45 kJ=-45000 J (with negative sign since it is released by the system), and the work done is W=-855 J still with negative sign because it is performed by the system on the surrounding, so the change in internal energy is
\Delta U = Q +W=-45000 J - 855 J=-45855 J
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3 years ago
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