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Aleksandr [31]
3 years ago
14

you are flying a kite that has two strings attached to either side of it you are holding those strings in your left and right ha

nd if you pull down with right hand which direction will it move
Physics
2 answers:
Svetach [21]3 years ago
8 0
The kite would move to the right as well
lys-0071 [83]3 years ago
5 0

Answer:

Suppose that originally the kite is parallel to the ground, there is no force of the wind pushing it to neither side.

Now, if you pull the right side of the kite down, the left side will rise a little bit, and now there will be a surface where the wind cand apply pressure, and in this case, the pressure will be applied to the side with the lower part (in this case the right direction)

so the direction in which the kite will move is also right.

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Explanation:

molecules of teacup have more avg. kinetic energy

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Se ha quemado magnesio (reacción con el oxígeno) y se obtuvieron 12g de óxido de magnesio (II). ¿Cuánto magnesio se quemó? ¿Qué
Sedaia [141]

Answer:

The first answer is 7,24g Mg

The second answer is 3,36L O2

Explanation:

Atomic masses: Mg= 24,3 ; O=16

Solution: MMgO = 40,3 g/mol

2 Mg + O2 => 2 MgO

1) 12 g MgO x (2x24,3 g Mg / 2x 40,3 MgO) = 7,24 g Mg

2)

At  first calculate moles from Oxygen:

12 g MgO x ( 1 mol from Oxygen/ 2 x 40,3 g MgO ) = 0,15 moles from Oxygen

then ....

0,15 moles from Oxygen x (22,4 lts / 1 mol from Oxygen ) = 3,36 lts

22.4 liters is the constant that we use in this equation, it is a value that is repeated since we are in the presence of a gas with ideal behavior, so it is considered that the normal molar volume of ideal gaseous substances is always 22.4 liters, estimated with a temperature of 0º C and a pressure of 1 atmosphere. (constant temperature and pressure)

7 0
3 years ago
Susie blows up a balloon. First, she places the balloon in a bucket of ice water. She observes the balloon. She then removes the
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Given: G = 6.67259 × 10−11 N m2 /kg2 . A 438 kg geosynchronous satellite orbits a planet similar to Earth at a radius 1.94 × 105
photoshop1234 [79]

Answer:

449.37412 N

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m = Mass of satellite = 438 kg

M = Mass of planet

T = Time period of the satellite = 24 h

r = Radius of planet = 1.94\times 10^8\ m

The time period of the satellite is given by

T=2\pi\sqrt{\frac{r^3}{GM}}\\\Rightarrow M=4\pi^2\frac{r^3}{T^2G}\\\Rightarrow M=4\pi^2\times \frac{(1.94\times 10^8)^3}{(24\times 3600)^2\times 6.67259\times 10^{-11}}\\\Rightarrow M=5.78686\times 10^{26}\ kg

The gravitational force is given by

F=G\frac{Mm}{r^2}\\\Rightarrow F=6.67259\times 10^{-11}\times \frac{5.78686\times 10^{26}\times 438}{(1.94\times 10^8)^2}\\\Rightarrow F=449.37412\ N

The force acting on this satellite is 449.37412 N

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3 years ago
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