(1) The wavelength of the wave is 1.164 m.
(2) The velocity of the wave is 23.7 m/s.
(3) The maximum speed in the y-direction of any piece of the string is 6.14 m/s.
<h3>
Wavelength of the wave</h3>
A general wave equation is given as;
y(x, t) = A sin(Kx - ωt)
<h3>Velocity of the wave</h3>
v = ω/K
From the given wave equation, we have,
y(x, t) = 0.048 sin(5.4x - 128t)
v = ω/K
where;
- ω corresponds to 128
- k corresponds to 5.4
v = 128/5.4
v = 23.7 m/s
<h3>Wavelength of the wave</h3>
λ = 2π/K
λ = (2π)/(5.4)
λ = 1.164 m
<h3>Maximum speed of the wave</h3>
v(max) = Aω
where;
- A is amplitude of the wave
- ω is angular speed of the wave
v(max) = (0.048)(128)
v(max) = 6.14 m/s
Thus, the wavelength of the wave is 1.164 m.
The velocity of the wave is 23.7 m/s.
The maximum speed in the y-direction of any piece of the string is 6.14 m/s.
Learn more about wavelength here: brainly.com/question/10728818
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Well, Air resistance is a special type of friction (you cannot classify it in other categories). That force of air-resistance is often observed to oppose the motion of the object,( like every other frictional forces)
Hope this helps!
Answer:
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Answer with Explanation:
We are given that mass of block=0.0600 kg
Initial speed of block=0.63 m/s
Distance of block from the hole when the block is revolved=0.47 m
Final speed=3.29 m/s
Distance of block from the hole when the block is revolved=
a.We have to find the tension in the cord in the original situation when the block has speed =
Because tension is equal to centripetal force
Substitute the values
b.
c.Work don=Final K.E-Initial K.E
Icy/Snowy roads have less friction than normal roads. This means that the wheels are less likely to stay positioned because of traction, and you will spin out of control
