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Arte-miy333 [17]
3 years ago
9

A block on a rough, horizontal surface is attached to a horizontal spring of negligible mass. The other end of the spring is att

ached to a wall. The spring is
compressed such that the block is located at position X. When the block-spring system is released, the block travels to the right through position Y and
continues to travel to the right through position Z. Free body diagrams for the block at positions X, Y, and Z are shown in the figure. At which position does the
block have the greatest kinetic energy?
A
х
B
Y
Z
The answer cannot be determined without knowing the exact speed of the block at each position.

Physics
1 answer:
Mekhanik [1.2K]3 years ago
7 0

Answer:

Z

Explanation:

It has the least potential energy in the spring because the spring expanded all the way meaning it is going the fastest

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Two frisky grasshoppers collide in midair at the top of their respective trajectories and grab onto each other, holding tight th
Svetlanka [38]

Answer:

The decrease in Kinetic energy is 0.0107 Joules

Explanation:

Given

Mass of grasshoppers

Let m1 = Mass of grasshopper 1

Let m2 = Mass of grasshopper 2

Let u1 = initial speed of grasshopper 1

Let u2 = initial speed of grasshopper 2

m1 = 250g = 0.25kg

m2 = 130g = 0.13kg

u1 = 15cm/s = 0.15m/s

u2 = 65cm/s = 0.65m/s

First, we calculate the final velocity of the grasshoppers after collision using conservation of momentum.

Using

m1u1 + m2u2 = (m1 + m2) * v

Where v = final velocity

By substituton

0.25 * 0.15 + 0.13 * 0.65 = (0.25 + 0.13) * v

0.0375 + 0.0845 = 380v

0.122 = 0.38v

Make v the subject of formula

v = 0.122/0.38

v = 0.321 m/s

Calculating the Kinetic energies before and after impact.

Before collision;

KE = ½m1u1²+ ½m2u2²

KE = ½(m1u1² + m2u2²)

By substituton;

KE = ½(0.25 * 0.15² + 0.13 * 0.65²)

KE = 0.030275J

After collision:

KE = ½(m1+m2)v²

KE = ½(0.25 + 0.13) * 0.321²

KE = 0.01957779 J

Change in kinetic energy = ∆KE

∆KE = 0.030275J - 0.01957779J

∆KE = 0.01069721J

∆KE = 0.0107 J --- Approximately

Hence the decrease in Kinetic energy is 0.0107 Joules

7 0
3 years ago
Stephanie lives in California, and her cousin Thomas lives in France. Which coordinate system would be most useful if the two wa
abruzzese [7]

I think it is B... not 100% tho

3 0
4 years ago
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a shot putter accelerates a 7.3kg shot from rest to 14m/s in 1.5r seconds. what average power was developed?
Sedaia [141]

Explanation:

power =  \frac{energy \: expended}{time}

m = 7.3kg

u = 0

v = 14m/s

t = 1.5sec

P = (0.5×7.3×14²) ÷ 1.5

P = 476.93

P = 477 watt

3 0
4 years ago
In Part C, how would the effects differ if you connected the galvanometer to the primary coil and the battery/switch to the seco
Katen [24]

N₂ / N₁ = 13.3

A transformer is a device that changes the voltage in the primary, causing a voltage to be induced in the secondary. The expression for this voltage ratio is

ΔV₂ = N₂ /N₁ ΔV₁

where N is the number of windings on each side and V2 and V1 are the voltages in the secondary and primary, respectively.

They state that the primary voltage in this instance is 9.0 V and the secondary voltage is 120 V.

ΔV₂ /ΔV₁ = N₂ / N₁

N₂ / N₁ = 120/9

N₂ / N₁ = 13.3

Learn more about  voltage here brainly.com/question/16774947

#SPJ4.

A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secondary coil is connected to a light bulb that operates on 120 V. Determine the ratio of the secondary to primary turns needed for the bell's transformer. Determine the ratio of the secondary to primary turns needed for the bells transformer. Ns/Np=?

4 0
2 years ago
Why do the stars rotate​
Aloiza [94]

Answer:

Angular momentum

Explanation:

Stars are formed as a result of a collapse of a low-temperature cloud of gas and dust. During the colapse conservation of angular momentum causes any small net rotation of the cloud to increase thus forcing the material into rotating

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3 years ago
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