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AVprozaik [17]
3 years ago
11

A 570-g squirrel with a surface area of 880 cm2 falls from a 5.2-m tree to the ground. Estimate its terminal velocity. (Use the

drag coefficient for a horizontal skydiver. Assume that the cross-sectional area of the squirrel can be approximated as a rectangle of width 11.2 cm and length 22.4 cm. Note, the squirrel may not reach terminal velocity by the time it hits the ground. Give the squirrel's terminal velocity, not it's velocity as it hits the ground.)
Physics
1 answer:
Nostrana [21]3 years ago
3 0

Answer : v = 14.28 m/s

Explanation :

It is given that,

mass of squirrel, m=570\ g

Surface area, A=880\ cm^2=88\times 10^{-3}

Height, h=5.2\ m

Terminal velocity is given by :

v_t=\sqrt{\dfrac{2mg}{\rho AC}

where, \rho is density of fluid which is falling and it is given by

\rho=\dfrac{m}{V}

since, volume=area\times height

so, \rho=\dfrac{0.57\ Kg}{0.088\ m^2\times 5.2\ m}

\rho=1.24\ Kg/m^3

A is the surface area of squirrel.

C is the drag coefficient.

The surface area facing the fluid is given by : A_f=\dfrac{0.088\ m^2}{2}=0.044\ m^2

so, terminal velocity is :

v_t=\sqrt{\dfrac{2\times 0.57\ Kg\times 9.8\ m/s^2}{1.24\ Kg/m^3\times 0.044\ m^2\times 1}}

v_t=\sqrt{ 204}

v_t=14.28\ m/s

<em>So, the terminal velocity of squirrel is 14.28 m/s.</em>

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Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.23 2.23 times a second. A tack is stuck in the t
elena-14-01-66 [18.8K]

Explanation:

The given data is as follows.

       Angular velocity (\omega) = 2.23 rps

     Distance from the center (R) = 0.379 m

First, we will convert revolutions per second into radian per second as follows.

             = 2.23 revolutions per second

             = 2.23 \times 2 \times 3.14 rad/s

             = 14.01 rad/s

Now, tangential speed will be calculated as follows.

  Tangential speed, v = R \times \omega

                               = 0.379 x 14.01

                               = 5.31 m/s

Thus, we can conclude that the tack's tangential speed is 5.31 m/s.

8 0
3 years ago
2. Use the diagram below to answer this question. As the ball moves from point A to C what is happening to the energy? Explain t
OLga [1]

Answer/Explanation:

The highest point of potential energy is A, when the ball rolls down the hill potential energy decreases and kinetic energy decreases, but the total energy is constant no matter what. This means the energy does not go away but instead is transferred to a different form.

A: most potential and least kinetic

B: losing potential gaining kinetic

C: losing more potential and gaining more kinetic

D: most kinetic and least potential

E: Gaining  potential and losing kinetic

F: Gaining more potential and losing more kinetic

G: more potential than kinetic but not the most potential

<u>Have a great day and mark me brainliest! :)</u>

5 0
3 years ago
Read 2 more answers
The magnetic flux that passes through one turn of a 22-turn coil of wire changes to 2.5 Wb from 13.0 Wb in a time of 0.052 s. Th
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Answer: The resistance of the wire is 17.1 ohms

Explanation: Please see the attachments below

5 0
3 years ago
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Can an igneous rock become another igneous rock? If so, how?
MArishka [77]

Yes a igneous rock can be changed into another igneous rock. the reason behind it is when rocks melt they become magma or lava. when lava flows on the surface of the earth it crystallizes quickly and makes small crystals. but when they cool slower they make larger crystals. yes igneous rocks can change but only through extreme temperatures.

5 0
3 years ago
1. Your big brother, despite warning, drops a penny off the observation
Tpy6a [65]

Answer:

The marble will take 8.813 seconds to hit the ground.

Explanation:

The marble will fall according to this motion equation: y(final) = y(initial) + v(initial)×t + 1/2×a×t×t

y(final)=0 m, the marble's final position in relation to the ground

y(initial)=381 m, the marble's initial position in relation to the ground

v(initial)=0 m/s (meters per second), the marble's initial velocity (speed with direction) when fall first begins

t=? seconds, this is the amount of time that passes while falling, the variable in this problem

a=-9.81 m/s/s, the rate at which the velocity of the marble changes, acceleration. On Earth, neglecting friction, acceleration is a constant at negative 9.81 meters per second squared

Plug the values into the equation: 0= 381 + 0t + 1/2(-9.81)(t)(t)

Subtract 381 from both sides and disregard 0t because it has no value and no longer matters: -381= 1/2(-9.81)(t)(t)

Multiply out the equation: -381= -4.905(t)(t)

Divide both sides by -4.905 to isolate the variable: 77.676=(t)(t)

Find the square root of both sides: t=8.813 seconds

4 0
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