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3 years ago

A large box slides across a frictionless surface with a velocity of 12 m/s and a mass of 4

1 answer:

3 0

Answer= 8m/s

Because total Momentum before= total momentum after

Momentum before (p=mu)
p=(4)(12)= 48
p=2(0)=0
So total momentum before=48

Momentum after (p=mu)
Masses combined —2+4=6kg
p=6u

Mb=Ma
48=6u
u=8m/s

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A 60-kg rollerblader rolls 10 m down a 30? incline. When she reaches the level floor at the bottom, she applies the brakes. The

VARVARA [1.3K]

Answer:

s = 20 m

Explanation:

given,

mass of the roller blader = 60 Kg

length = 10 m

inclines at = 30°

coefficient of friction = 0.25

using conservation of energy

$\dfrac{1}{2}mu^2 = m g d sin \theta$

$u^2 = 2 g d sin30^0$

$u= \sqrt{2\times 9.8 \times 10 sin30^0}$

u = 9.89 m/s

Using second law of motion

ma =μ mg

a = μ g

a = 0.25 x 9.8

a = 2.45 m/s²

Using third equation of motion ,

v² - u² = 2 a s

0² - 9.89² = 2 x 2.45 x s

s = 20 m

the distance moved before stopping is 20 m

3 0

4 years ago

Allison is looking through a telescope at an object in space. The object looks like a very small planet, and it does not have a

Verizon [17]

Answer:

Allison is probably looking at the asteroid.

Explanation:

Asteroids are the giant gas balls of inner solar system that are present in the space.
Asteroids orbits around the sun in very irregular ans strange path unlike the other planets.
This is also the reason why it's called as the minor planets.
It could have been comet but if it had been a comets he must have seen the tail but asteroids do not have any tail like structure.

8 0

3 years ago

A chamber fitted with a piston contains 1.90 mol of an ideal gas. Part A The piston is slowly moved to decrease the chamber volu

yarga [219]

Answer:

The work done is 5136.88 J.

Explanation:

Given that,

n = 1.90 mol

Temperature = 296 K

If the initial volume is V then the final volume will be V/3.

We need to calculate the work done

Using formula of work done

$W=nRT\ ln(\dfrac{V_{f}}{V_{i}})$

Put the value into the formula

$W=1.90\times8.314\times296\ ln(\dfrac{\dfrac{V}{3}}{V})$

$W=1.90\times8.314\times296\ ln(\dfrac{1}{3})$

$W=−5136.88\ J$

The Work done on the system.

Hence, The work done is 5136.88 J.

5 0

3 years ago

Which statement provides the best description of a computational model?

Varvara68 [4.7K]

Answer:

The answer is "Option C".

Explanation:

Computation modeling is used as the software for math, physics, or software engineering in the simulation and study of complicated processes. The software framework incorporates many parameters, that characterize the model under study. It is a computer program, in which the mathematical formula is generated by computers and research complex systems.

4 0

3 years ago

If a ball has a velocity of 5 m/s and a kinetic energy of 1000 J, what is its mass?

zheka24 [161]

Answer: I don't know how to do this

Explanation: sorry I am not sure.

7 0

3 years ago