Answer:
Explanation:
For circuit in resonance , inductive and capacitive reactance should be equal. Since in the given circuit , these two are not equal, the circuit is not in resonance. It does not depend upon voltage provided.
option b is correct.
With this load, the fraction of the average power, put out by the source of emf, delivered to the load can be calculated as follows
Power delivered to resistor will be 2/3 rd of total power delivered by source because resistance has value twice that of reactance of capacitor. So the correct option is .7
option D ) is correct.
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Answer:
313 K or 40 degree celsius.
Explanation:
Initial
, 
Now, final
Combined the ideal gas law
Therefore, the final temperature of ideal gas is 313 K.
Answer: a. F doubled
b. F reduced by one-quarter i.e
1/4*(F)
c. 1/9*(F)
d. F increased by a factor of 4 i.e 4*F
e. F reduces 3/4*(F)
Explanation: Coulombs law states the force F of attraction/repulsion experience by two charges qA and qB is directly proportional to thier product and inversely proportional to the square of distance d between them. That is
F = k*(qA*qB)/d²
a. If qA is doubled therefore the force is doubled since they are directly proportional.
b. If qA and qB are half, that means thier new product would be qA/2)*qB/2 =qA*qB/4
Which means the product of charge is divided by 4 so the force would be divided by 4 too since they are directly proportional.
c. If d is tripped that is multiplied by 3. From the formula new d would be (3*d)²=9d² but force is inversely proportional to d² so instead of multiplying by 9 the force will be divided by 9
d. If d is cut into half that is divided by 2. The new d would be (d/2)²=d²/4. So d² is divided by 4 so the force would be multiplied by 4
e. If qA is tripled that is multiplied by 3. F would be multiplied by 3 also, if at the same time d is doubled (2*d)²= 4*d² . Force would be divided by 4 at same time. So we have,
3/4*F
Answer:
I hope 2 amperes of current passes
