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uysha [10]
2 years ago
12

A large box slides across a frictionless surface with a velocity of 12 m/s and a mass of 4

Physics
1 answer:
denpristay [2]2 years ago
3 0
Answer= 8m/s

Because total Momentum before= total momentum after

Momentum before (p=mu)
p=(4)(12)= 48
p=2(0)=0
So total momentum before=48

Momentum after (p=mu)
Masses combined —2+4=6kg
p=6u


Mb=Ma
48=6u
u=8m/s
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motikmotik

Answer:

0.79 s

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We have to calculate the employee acceleration, in order to know the minimum time. According to Newton's second law:

\sum F_x:f_{max}=ma_x\\\sum F_y:N-mg=0

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8 0
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