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3 years ago

9

A

1 answer:

deff fn [24]3 years ago

4 0

Answer:

The concentration given here is in terms of molality which is moles of solute per kg of solution. Therefore, we multiply the concentration by the total mass of the solution and obtain the moles of solute. We can convert this into grams and calculate for the solvent.

0.630 mol KBr / kg solution ( .086 kg solution ) = 0.0542 mol KBr

0.0542 mol Kbr ( 119.002 g / 1 mol ) = 6.4475 g KBr

Mass of solvent = 86 - 6.4475 = 79.55 g water

Explanation:

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2 years ago

HC2H3O2 (aq) + H2O (l) ⇔ C2H3O2- (aq) + H3O+ (aq) Ka = 1.8 x 10-5

marin [14]

The concentration of [H3O⁺]=2.86 x 10⁻⁶ M

<h3>Further explanation</h3>

In general, the weak acid ionization reaction

HA (aq) ---> H⁺ (aq) + A⁻ (aq)

Ka's value

$\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}$

Reaction

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$\tt Ka=\dfrac{[C_2H_3O^{2-}[H_3O^+]]}{[HC_2H_3O_2]}}\\\\1.8\times 10^{-5}=\dfrac{0.22\times [H_3O^+]}{0.035}$

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3 years ago