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For a volume of 27,000 L to a pressure of 0.82 atm at 25 °C, the amount of N2 is required is mathematically given as
n=1.1*10^{-3}mole
<h3>What amount of N2 is required to fill a small room with a volume of 27,000 L to a pressure of 0.82 atm at 25 °C?</h3>Generally, the equation for the ideal gas is mathematically given as
PV=nRT
Therefore
n=1.1*10^{-3}mole
In conclusion, the amount of N2 is required is
n=1.1*10^{-3}mole
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2.04 atm is the pressure of the nitrogen gas in the container when 0.316 mol sample of nitrogen gas, N2 (g), is placed in a 4.00 L container at 315 K.
Explanation:
Data given:
moles of nitrogen gas, n = 0.316
volume of the nitrogen gas, V = 4 litres
temperature of the container of nitrogen gas = 315 K
R (gas constant) = 0.08201 Latm/mole K
Pressure of the nitrogen gas on the container, P = ?
from the data given, we will apply ideal gas law equation to calculate the pressure on the nitrogen gas:
PV = nRT
Rearranging the equation,
P =
P =
P = 2.04 atm
The pressure of the nitrogen gas in the container is 2.04 atm.