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saveliy_v [14]
3 years ago
10

An animal cell has a 0.9% saline environment is placed into a solution that is 9% saline. What will happen to the cell

Chemistry
1 answer:
Softa [21]3 years ago
7 0

The concentration of cell is less than that of the solution .

Hence the cell will be called as hypotonic and the solution will be called as hypertonic.

in order to balance the concentration on the two sides of cell (inside and outside in the solution) there will be movement of solvent particles (through semipermeable membrane ) from cell (lower concentration of solute) to solution (higher concentration of solute).

Thus cell will shrink.



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How many moles of PC15 can be produced from 58.0 g of Cl₂ (and excess<br> P4)?
ludmilkaskok [199]

0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess

P4)

<h3>How to calculate moles?</h3>

The balanced chemical equation is

P_{4}  + 10Cl_{2}  = 4PCl_{5}

The mass of clorine is m(Cl_{2}) = 58.0 g

The amount of clorine is n(Cl_{2}) = m(Cl_{2})/M(Cl_{2}) = 58/70.906 = 0.817 mol

The stoichiometric reaction,shows that

10 moles of Cl_{2} yield 4 moles of PCl_{5};

0.817 of Cl_{2} yield x moles of PCl_{5}

n(PCl_{5}) = 4*0.817/10 = 0.3268 mol

To know more about stoichiometric reaction, refer:

brainly.com/question/14935523

#SPJ9

3 0
1 year ago
Quick help I really need help
Sauron [17]

Answer:

CO2 H2o

Explanation:

8 0
3 years ago
What is the charge of a carbon ion that has gained 4 electrons?
olya-2409 [2.1K]

Answer:

Negative

Explanation:

Any atom gaining electrons will get a negative change since the charge of the electron is negative.

6 0
3 years ago
Describe what is happening in this chemical equation: Al2(SiO3)3 + NaOH → Na(SiO3)3 + Al2OH Please Help ASAP
WITCHER [35]

Answer:

Double replacement reaction

Explanation:

This is what is known as a double replacement reaction. The two parts of each molecule separate and recombine to form two new compounds. For instance, Al_2(SiO_3)_3 separates into Al_2 and (SiO_3)_3, while NaOH separates into Na and OH, and then they recombine with the other compound.

Hope this helps!

7 0
3 years ago
Read 2 more answers
Express the concentration of a 0.0610 m aqueous solution of fluoride, f–, in mass percentage and in parts per million. assume th
ASHA 777 [7]
<span>Assume you have 1 L of solution.
Moles F- = M F- x L F- = (0.0610)(1) = 0.0610 moles F-
0.0610 moles F- x(19.0 g F-/1mole F-) = 1.159 g F- in 1 L of solution
1 L solution x (1000 mL / 1 L) x (1.00 g / mL) = 1000 g of solution
mass % F- = (g F- / g solution) x 100 = (1.159 / 1000) x 100
= 0.1159%
parts per million F- = mg F- /L = 1159 / 1 = 1159 ppm F-</span>
8 0
3 years ago
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