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saveliy_v [14]
3 years ago
10

An animal cell has a 0.9% saline environment is placed into a solution that is 9% saline. What will happen to the cell

Chemistry
1 answer:
Softa [21]3 years ago
7 0

The concentration of cell is less than that of the solution .

Hence the cell will be called as hypotonic and the solution will be called as hypertonic.

in order to balance the concentration on the two sides of cell (inside and outside in the solution) there will be movement of solvent particles (through semipermeable membrane ) from cell (lower concentration of solute) to solution (higher concentration of solute).

Thus cell will shrink.



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Explanation:

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So, 100.0 L volume of NH_3will be occupied by :

\frac{1}{22.4 L}\times 100.0 L=4.4642 moles

According to reaction 2 moles NH_3 are obtained from 1 mole of N_2.

Then,4.4642 moles of NH_3 will be obtained from :

\frac{1}{2}\times 4.4642 that is 2.2321 moles of N_2

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2.2321 mol\times 28 g/mol=62.4988\approx 62.50 g

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4 0
3 years ago
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