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zhenek [66]
3 years ago
15

HELP PLEASEEEEEEEEEEEEEEEEEE I CANT GO CANRVIL IF I CANT PASS THIS THEY WANNA SEE MY GRADES AND THIS WILL HELP ME GET MY GRADES

UP AND IM DOING ANOTHER QUESTION FOR THE REST OF THE PICS AND 30 POINTS!!! 6.5A Questions 1-6 are from Lesson 1.01. Directions: Identify the models in each picture as an element or a compound. Question 1 (Mandatory) (2 points) Saved Question 1 options: Question 2 (Mandatory) (2 points) Saved Question 2 options: Question 3 (Mandatory) (2 points) Question 3 options: Question 4 (Mandatory) (2 points) Question 4 options: Question 5 (Mandatory) (2 points) Question 5 options: Question 6 (Mandatory) (2 points) Question 6 options: 6.5B Questions 7-10 are from Lesson 1.01. Directions: Label each graph as either: Earth's Atmosphere, Earth's Crust, Earth's Oceans, or Life on Earth. Question 7 (Mandatory) (2 points) Question 7 options: Question 8 (Mandatory) (2 points) Question 8 options: Question 9 (Mandatory) (2 points) Question 9 options: Question 10 (Mandatory) (2 points) Question 10 options: 6.5C Questions 11-15 are from Lesson 1.02. Directions: Use the mnemonic to identify which type of evidence of a possible chemical change is shown. 6.5 Matter and energy. The student knows the difference between elements and compounds. The student is expected to: (C) identify the formation of a new substance by using the evidence of a possible chemical change such as production of a gas, change in temperature, production of a precipitate, or color change. Question 11 (Mandatory) (2 points) Question 11 options: Question 12 (Mandatory) (2 points) Question 12 options: Question 13 (Mandatory) (2 points) Question 13 options: Question 14 (Mandatory) (2 points) Question 14 options: Question 15 (Mandatory) (2 points)

Chemistry
1 answer:
Daniel [21]3 years ago
4 0

Answer:

3,3453 thank me later

Explanation:

1,3433

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How many mL of a stock solution of 2.00 M KNO3 are needed to prepare 100.0 mL of 0.15M KNO3? with work plz
Tatiana [17]
Using the law of dilution :

Mi x Vi =  Mf x Vf

2.00 x Vi = 0.15 x 100.0

2.00 x Vi = 15

Vi = 15 / 2.00

Vi = 7.5 mL

hope this helps!


3 0
3 years ago
How many oxygen atoms are present in 30g of glucose?
Alex17521 [72]
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5 0
3 years ago
What mass of solute must be used to prepare 500ml of 0.100M aqueous sodium borate Na2B4O7 from solid hydrated sodium borate Na2B
motikmotik

0.000132 g of hydrated sodium borate (Na₂B₄O₇ · 10 H₂O)

Explanation:

First we need to find the number of moles of sodium borate (Na₂B₄O₇) in the solution:

molar concentration = number of moles / volume (L)

number of moles = molar concentration × volume (L)

number of moles of Na₂B₄O₇ = 0.1 × 0.5 = 0.05 moles

We know now that we need 0.05 moles of hydrated sodium borate (Na₂B₄O₇ · 10 H₂O) to make the solution.

Now to find the mass of hydrated sodium borate we use the following formula:

number of moles = mass / molar weight

mass =  number of moles × molar weight

mass of hydrated sodium borate = 0.05 / 381 = 0.000132 g

Learn more about:

molar concentration

brainly.com/question/14106518

#learnwithBrainly

4 0
3 years ago
Using a chemical equation to find moles of product from moles...
kaheart [24]

Answer: 0.600 moles

Balanced eqn for decomposition of the rocket fuel:

2 NH4ClO4 (s) ----> N2 (g) + Cl2 (g) + 2 O2 (g) + 4 H2O (g)

Since, 2 moles of NH4ClO4 produces 2 moles of O2 gas, this means that 0.6 moles of NH4ClO4 will produce 0.6 moles of O2 gas

7 0
1 year ago
Lead can be prepared from galena [lead(II) sulfide] by first roasting the galena in oxygen gas to form lead(II) oxide and sulfur
Vesna [10]

Answer:

a) Step 1:

2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)

Step 2:

2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)

b) The overall balanced reaction for given process is ;

3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)

Explanation:

a)

Galena = PbS

Lead(II) oxide = PbO

Sulfur dioxide = SO_2

Step 1:

Roasting the galena in oxygen gas to form lead(II) oxide and sulfur dioxide.

Balanced equation of step 1:

2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)..[1]

Step 2:

Heating the metal oxide with more galena forms the molten metal and more sulfur dioxide.

Balanced equation of step 2:

2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)..[2]

b)

For over all reaction add [1] and [2]. The overall balanced reaction for given process is ;

3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)

5 0
3 years ago
Read 2 more answers
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