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zhenek [66]
3 years ago
15

HELP PLEASEEEEEEEEEEEEEEEEEE I CANT GO CANRVIL IF I CANT PASS THIS THEY WANNA SEE MY GRADES AND THIS WILL HELP ME GET MY GRADES

UP AND IM DOING ANOTHER QUESTION FOR THE REST OF THE PICS AND 30 POINTS!!! 6.5A Questions 1-6 are from Lesson 1.01. Directions: Identify the models in each picture as an element or a compound. Question 1 (Mandatory) (2 points) Saved Question 1 options: Question 2 (Mandatory) (2 points) Saved Question 2 options: Question 3 (Mandatory) (2 points) Question 3 options: Question 4 (Mandatory) (2 points) Question 4 options: Question 5 (Mandatory) (2 points) Question 5 options: Question 6 (Mandatory) (2 points) Question 6 options: 6.5B Questions 7-10 are from Lesson 1.01. Directions: Label each graph as either: Earth's Atmosphere, Earth's Crust, Earth's Oceans, or Life on Earth. Question 7 (Mandatory) (2 points) Question 7 options: Question 8 (Mandatory) (2 points) Question 8 options: Question 9 (Mandatory) (2 points) Question 9 options: Question 10 (Mandatory) (2 points) Question 10 options: 6.5C Questions 11-15 are from Lesson 1.02. Directions: Use the mnemonic to identify which type of evidence of a possible chemical change is shown. 6.5 Matter and energy. The student knows the difference between elements and compounds. The student is expected to: (C) identify the formation of a new substance by using the evidence of a possible chemical change such as production of a gas, change in temperature, production of a precipitate, or color change. Question 11 (Mandatory) (2 points) Question 11 options: Question 12 (Mandatory) (2 points) Question 12 options: Question 13 (Mandatory) (2 points) Question 13 options: Question 14 (Mandatory) (2 points) Question 14 options: Question 15 (Mandatory) (2 points)

Chemistry
1 answer:
Daniel [21]3 years ago
4 0

Answer:

3,3453 thank me later

Explanation:

1,3433

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How many moles are equal to 1.4 x 10^24 atoms of aluminum
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Answer: 2.3 moles

Explanation:

Recall that based on Avogadro's law, 1 mole of any substance has 6.02 x 10^23 atoms

So if 1 mole of Aluminum = 6.02 x 10^23 atoms

Then, Z moles = 1.4 x 10^24 atoms

To get the value of Z, we cross multiply:

1 mole x 1.4 x 10^24 atoms = Z x (6.02 x 10^23 atoms)

1.4 x 10^24 atoms = Z x (6.02 x 10^23)

Hence, Z = (1.4 x 10^24 atoms) ➗ (6.02 x 10^23 atoms)

Z =2.3 moles

Thus, there are 2.3 moles in 1.4 x 10^24 atoms of aluminum.

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