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olya-2409 [2.1K]
3 years ago
6

How is a cold air mass similar to a mountain range as to the effect on a warm air mass?

Physics
1 answer:
Fittoniya [83]3 years ago
8 0
Different types of fronts produce different patterns of weather. When a cold, dense air mass pushes warmer air, it produces a cold front. A cold front can turn a heat wave into normal summer weather or turn cold winter air into very cold weather. Cold fronts often produce tall cumulonimbus clouds.
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How do I use the equation E=MC^2 in relation to atoms to find the amount of energy of a reaction?
Tomtit [17]
-- Find the mass of all the pieces before the reaction.

-- Find the mass of all the pieces after the reaction.

-- Find the difference . . . (mass before) minus (mass after)

-- If any mass is missing, either you lost track of it, or else
it was converted to energy.

How much energy ?

(the missing mass) times c² .
5 0
3 years ago
Two trains, each having a speed of 28 km/h, are headed at each other on the same straight track. A bird that can fly 60 km/h fli
Semenov [28]

Answer:

The value is D =  70.71 \ km

Explanation:

From the question we are told that

The speed of each train is v =  28 \  km/h

The speed of the bird is v_1 =  60 \  km/h

The distance between the trains is d =  66 \  km

Generally the time taken before the collision occurs is mathematically represented as

t =  \frac{d}{2 * v}

=> t =  \frac{66 }{2 *  28}

=> t = 1.18 \  h

The total distance covered by the bird is mathematically represented as

D =  v_1 *  t

=>   D =  60 * 1.18

=>   D =  70.71 \ km

7 0
3 years ago
A small sculpture made of brass (rho brass = 8470 kg/m 3 ) is believed to have a secret central cavity. The weight of the sculpt
GaryK [48]

Answer:

Volume of secret cavity = 4 x 10⁻⁶m³

Explanation:

The weight of the sculpture in air is 15.76 N

Mass of the sculpture = 1.61 kg

Mass = Volume x Density

1.61 = V x 8470

Volume of brass =1.90 x 10⁻⁴ m³

When it is submerged in water, the weight is 13.86 N.

That is

  Weight of sculpture - Weight of water displaced = 13.86 N

  15.76 - Weight of water displaced = 13.86

   Weight of water displaced = 1.9 N

   Mass of water displaced = 0.194 kg

 Mass = Volume x Density

  0.194 = V x 1000

  Volume of water displaced =1.94 x 10⁻⁴ m³

Volume of secret cavity =  Volume of water displaced - Volume of brass material

Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³

7 0
4 years ago
When it is winter in the northern hemisphere we are receiving?
Vitek1552 [10]

Answer:

indirect sunlight

Explanation:

we're receiving some sunlight, but not much, if it's winter in one place, it's summer in another

8 0
3 years ago
Read 2 more answers
If you wished to warm 100 kg of water by 15 degrees celsius for your bath, how much heat would be required? (give your answer in
Anit [1.1K]
For the answer to the question above, 
<span>Q = amount of heat (kJ) </span>
<span>cp = specific heat capacity (kJ/kg.K) = 4.187 kJ/kgK </span>
<span>m = mass (kg) </span>
<span>dT = temperature difference between hot and cold side (K). Note: dt in °C = dt in Kelvin </span>

<span>Q = 100kg * (4.187 kJ/kgK) * 15 K </span>
<span>Q = 6,280.5 KJ = 6,280,500 J = 1,501,075.5 cal</span>
6 0
3 years ago
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