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4 years ago

One of the following is correctly termed a substance, and the others are mixtures. The substance is-

Physics

2 answers:

harina [27]4 years ago

8 0

Answer:

Your answer should be C) iron.

Hope this helps. :-)

Naily [24]4 years ago

8 0

Answer:

Iron

Explanation:

Iron is a substance, unlike baked potato soup :)

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How are matter and substances related?

Sedbober [7]

Matter is anything that has mass and takes up space. Substances are types of matter that are pure. Just remember that matter has mass and they both start with "m." Substances are <u>types of matter</u>. Cheers, mimiisawesome5

4 0

4 years ago

Read 2 more answers

A string of length L= 1.2 m and mass m = 20g is under 400 N of tension, its two ends are fixed. a. How many nodes will you see i

ozzi

Answer:

(iii) 6

Explanation:

Part a)

Since it is given that both ends are fixed and it is vibrating in 5th harmonic

So here it will have 5 number of loops in it

so we can draw it in following way

each loop will have 1 antinode and two nodes which means number of nodes is one more than number of anti-nodes

So there are 5 loops which means it will have 5 antinodes

and hence there will be 6 nodes in it

so correct answer will be

(iii) 6

8 0

3 years ago

A bus has velocity of 20 m/s towards east and another bus has velocity of 15 m/s in west direction . if they start to move from

Snezhnost [94]

Answer:

3.8 km

Explanation:

Eastern Side Bus

Velocity = 20m/s

Covers distance in 2 min (120sec) = 20×120 = 2400m = 2 km

Western Side Bus

Velocity = 15m/s

Covers distance in 2 min (120sec) = 15×120 = 1800m = 1.8 km

Separation Distance = 2+1.8 = 3.8 km

7 0

3 years ago

A block of metal has a width of 3.2 cm, a length of 17.1 cm, and height of 5.3 cm . Its mass is 1.5 kg . Calculate the density o

professor190 [17]

Answer:

0.00517kg/cm³

Explanation:

Density = Mass/Volume

Given

Mass= 1.5kg

Volume = 3.2cm×17.1cm×5.3cm

Volume = 290.016cm³

Get the density

Density = 1.5/290.016

Deñsity = 0.00517kg/cm³

8 0

3 years ago

Help wit these questions someone.

romanna [79]

In series circuit, Req = R₁ + R₂ + R₃ + ···

In parallel circuit, $\frac{1}{Req} = \frac{1}{R1} + \frac{1}{R2} + \frac{1}{R3} +...$

total resistance in the upper branch = R₂ + R₃ = R₂ + 2

$\frac{1}{Req} = \frac{1}{R2+R3} + \frac{1}{R1}$

$\frac{1}{4} = \frac{1}{R2+2} +\frac{1}{6}$

R₂ + 2 = 12

R₂ = 10Ω

$\frac{1}{Req} = \frac{1}{R2+R3} + \frac{1}{R1}$

$\frac{1}{Req} = \frac{1}{2+1} + \frac{1}{4}$

Req = 1.7Ω

7 0

3 years ago