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just olya [345]
4 years ago
6

How to allow a support professional to view your screen?

Computers and Technology
1 answer:
tigry1 [53]4 years ago
7 0
Best and easiest way is to download a software called TeamViewer. You then have to give your ID and Password written in TeamViewer to your support professional. He also has to download TeamViewer to help you if you decide to use this solution.
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Create an application containing an array that stores eight integers. The application should call five methods that in turn:
Rus_ich [418]
<h2><u>Answer</u>:</h2>

public class ArrayMethodDemo {

   public static void main (String args[]) {

       int[] numbers = {12, 15, 34, 67, 4, 9, 10, 7};

       int limit = 12;

       display(numbers);

       displayReverse(numbers);

       displaySum(numbers);

       displayLessThan(numbers, limit);

       displayHigherThanAverage(numbers);

   }

   

   public static void display(int[] numbers) {

       

       //Message to be displayed before printing out the numbers

      System.out.print("Numbers in the array: ");

       

       //loop through the numbers in the array and print each number

       for(int x: numbers){

           System.out.print(x + " ");

       }

       

       //print a new line

       System.out.println();

   }

   

   public static void displayReverse(int[] numbers) {

       

       //Message to be displayed before printing out the reverse of the array

       System.out.print("Reverse of the array numbers: ");

       

       

       //loop through the array starting from the last index

       for(int i = numbers.length - 1; i > 0; i--){

           System.out.print(numbers[i] + " ");

       }

       

       //print a new line

       System.out.println();

   }

   

   public static void displaySum(int[] numbers) {

       

       //initialize the sum variable

       int sum = 0;

       

       //loop through the array and add each element to sum

       for(int i = 0; i < numbers.length; i++){

           sum += numbers[i];

       }

       

       //print out the sum

      System.out.println("Sum: "  + sum);

       

   }

   

   public static void displayLessThan(int[] numbers, int limit) {

       

       //Text to be displayed before printing values less than the limit

       System.out.print("Values less than limit (" + limit + "): ");  

       //loop through the array and print numbers lower than the specified limit

       for(int i = 0; i < numbers.length; i++){

           if(numbers[i] < limit){

               System.out.print(numbers[i] + " ");

           }

       }

       

       //print a new line

       System.out.println();

   }

   

   public static void displayHigherThanAverage(int[] numbers) {

       //initialize the average variable

       double average = 0.0;

       

       //initialize the sum variable

       int sum = 0;

       

       

       //loop through the array and add each element to sum

      for(int i = 0; i < numbers.length; i++){

           sum += numbers[i];

       }

       

       //calculate the average

      average = sum / numbers.length;

       

       //Message to be displayed before printing the values higher than the average

       System.out.print("Values higher than average (" + average + "): ");

       

       

       //loop through the array and print numbers higher than the calculated average

      for(int i = 0; i < numbers.length; i++){

           if(numbers[i] > average){

               System.out.print(numbers[i] + " ");

           }

       }

       

       //print a new line

       System.out.println();

   }

   

}

<h2><u>Sample Output:</u></h2>

Numbers in the array: 12 15 34 67 4 9 10 7  

Reverse of the array numbers: 7 10 9 4 67 34 15  

Sum: 158

Values less than limit (12): 4 9 10 7  

Values higher than average(19.0):34 67

<h2>Explanation:</h2>

The code above contains comments explaining important parts of the code. Kindly go through the comments. A sample output, arising from running the application, has also been added to ace understandability.

6 0
3 years ago
Encryption turns data into a form known as a ____.
tigry1 [53]
Cipher is the correct answer
8 0
4 years ago
In your own point of view, what is the importance of considering the relationship of the basic design concept like line, color,
bazaltina [42]

Answer:

future

Explanation:

4 0
3 years ago
When nearly all Americans in a recent survey said that they believe executives base decisions primarily on what will advance the
dlinn [17]

Answer:

serious concerns about.

Explanation:

Since the reports are indicating the almost all the Americans believe executive based decisions and it is a serious concern because the people should be taking their own decisions and the career decisions are the most important ones in a person's life. Depending on other to take decisions for you shows a weak character and lack of self-confidence.

6 0
3 years ago
Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a space. Ex: If origList =
Darya [45]

Answer:

#include <stdio.h>

int main(void) {

const int NUM_VALS = 4;

int origList[NUM_VALS];

int offsetAmount[NUM_VALS];

int i;

origList[0] = 20;

origList[1] = 30;

origList[2] = 40;

origList[3] = 50;

offsetAmount[0] = 5;

offsetAmount[1] = 7;

offsetAmount[2] = 3;

offsetAmount[3] = 4;

for(i=0;i<NUM_VALS;i++)

{

printf("%d ",origList[i]+offsetAmount[i]);

}

printf("\n");

return 0;

}

Explanation:

  • Initialize the origList and offsetAmount variables.
  • Loop up to the value of NUM_VALS variable.
  • Display the output by combining origList and offsetAmount.
5 0
3 years ago
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