1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dexar [7]
3 years ago
5

Now, examine the structures of benzhydrol and fluorene. Both compounds contain the same number of carbons but have very differen

t melting points. At first glance, one might expect benzhydrol to exhibit the higher melting point. Why might one think this?
Chemistry
1 answer:
zubka84 [21]3 years ago
4 0

Answer:

The OH group

Explanation:

Benzhydrol contains OH hydroxyl group in its molecule while fluorene does not. At first glance, one would think that OH, which contributes to hydrogen bonding would causes melting point of benzhydrol to be higher than fluorene. <em>However, </em>the structure of benzhydrol, which is 2 benzene rings connected to center hydroxyl carbon (PhCOHPh), allows for each benzene rings in benzhydrol to rotate until both rings are perpendicular to minimize repulsive force. This prevents the molecule from stacking on each other due to its non flat shape, and thus, lowering its melting point in contrast to flat fluorene molecule.

You might be interested in
What is one way a pathogen can enter the body?
Ipatiy [6.2K]
I’m pretty sure it’s Nose
8 0
3 years ago
Read 2 more answers
CHEMISTRY HELP !?????
zheka24 [161]

3. Plasma

- indefinite shape & volume

- affected by magnetic and electric field

- drift and flow freely


4. Liquids have fixed volume meaning packed tighter together as gases do not have fixed shape or volume .

D would be correct

8 0
4 years ago
Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

  1. C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
  2. H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
  3. 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

7 0
3 years ago
Determine which is the control group and which is the experimental group in the following scenario ( Scientists are testing a ne
Daniel [21]

Answer:

The group given the sugar pills.

Explanation:

The control group is the ones given sugar pills because they did not get the experimental aspirin

3 0
2 years ago
Read 2 more answers
I need help with these quickkk WILL GIVE BRAINLIEST PLS
DerKrebs [107]

Answer: number 2

Explanation:

8 0
3 years ago
Other questions:
  • 2. What is critical mass?
    15·1 answer
  • What does a Stationary object line look like?
    5·1 answer
  • Calculate the energy (in J/atom) for vacancy formation in silver, given that the equilibrium number of vacancies at 800 C is 3.6
    11·1 answer
  • For each store,what is the ratio of the number of cans to the price:24 packs (2 for 9);12 packs (4 for 10);12 packs (3 for 9)
    13·1 answer
  • I will give brainliest!!! What is the density of a sample of chlorine gas that exerts a pressure of 4.5 atm in a 12.6 L containe
    6·1 answer
  • Which of these methods could are used to separate an insoluble solid and soluble solid
    15·1 answer
  • If 27g of N2 reacts with 5.4g of H2, how much NH3 will be<br> produced?
    11·1 answer
  • Complete the nuclear reaction.*
    6·1 answer
  • The electron configuration of an element is 1s22s22p63s1. Describe what most likely happens when an atom of this element comes n
    12·1 answer
  • Boyle's law only works when a gas is kept at a constant temperature. Experimentally this is very tricky as changes in pressure o
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!