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The specific heat capacity of the given substance is -0.66 J/g°C.
<u>Explanation:</u>
The heat absorbed by any substance is the product of its mass, specific heat capacity and change in temperature.
q = m × c × ΔT
m is the mass in grams
q = amount of heat released or absorbed in J
ΔT = change in temperature in °C = 5 -50 = -45°C
c = specific heat capacity in J/g°C
c =
Plugin the values, we will get,
c =
= -0.66 J/g°C
Answer:
The essence including its given problem is outlined in the following segment on the context..
Explanation:
The given values are:
Moles of CO₂,
x = 0.01962
Moles of water,
Compound's mass,
= 0.4647 g
Let the compound's formula will be:
Combustion's general equation will be:
⇒
On putting the estimated values, we get
⇒
⇒
⇒
⇒
Now,
x : y : z =
=
=
=
So that the empirical formula seems to be "C₃H₆O₂".