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Svet_ta [14]
3 years ago
11

Please help ill give you a 100 points! Its urgent!! Q^Q

Chemistry
2 answers:
Sergio [31]3 years ago
8 0

Answer:

1. C.

Explanation:

djyliett [7]3 years ago
7 0

Answer:

?

Explanation:

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Carbon-14 has a half-life of approximately 5700 years. How much of a 1000g sample will be left undecayed and still radioactive a
Artist 52 [7]

Answer:

option C is correct (250 g)

Explanation:

Given data:

Half life of carbon-14 = 5700 years

Total amount of sample = 1000 g

Sample left after 11,400 years = ?

Solution:

First of all we will calculate the number of half lives passes during 11,400 years.

Number of half lives = time elapsed/ half life

Number of half lives = 11,400 years/5700 years

Number of half lives = 2

Now we will calculate the amount left.

At time zero = 1000 g

At first half life = 1000 g/2 = 500 g

At second half life = 500 g/2 = 250 g

Thus, option C is correct.

4 0
3 years ago
Which substance is a primary source of hydrocarbon
IceJOKER [234]

Answer:

Hydrocarbons are molecules consisting of both hydrogen and carbon. They are most famous for being the primary constituent of fossil fuels, namely natural gas, petroleum, and coal. For this reason, fossil fuel resources are often referred to as hydrocarbon resources.Jun 25, 2018

https://energyeducation.ca ›

6 0
3 years ago
What kind of questions do scientists ask?
Usimov [2.4K]

ones that are answered through observing :)

7 0
3 years ago
How many grams of Sg is required to produce 83.10 g SF6? S: +24F-->8SF
ozzi

Answer : The mass of S_8 required is 18.238 grams.

Explanation : Given,

Mass of SF_6 = 83.10 g

Molar mass of SF_6 = 146 g/mole

Molar mass of S_8 = 256.52 g/mole

The balanced chemical reaction is,

S_8+24F_2\rightarrow 8SF_6

First we have to determine the moles of SF_6.

\text{Moles of }SF_6=\frac{\text{Mass of }SF_6}{\text{Molar mass of }SF_6}=\frac{83.10g}{146g/mole}=0.569moles

Now we have to determine the moles of S_8.

From the balanced chemical reaction we conclude that,

As, 8 moles of SF_6 produced from 1 mole of S_8

So, 0.569 moles of SF_6 produced from \frac{0.569}{8}=0.0711 mole of S_8

Now we have to determine the mass of S_8.

\text{Mass of }S_8=\text{Moles of }S_8\times \text{Molar mass of }S_8

\text{Mass of }S_8=(0.0711mole)\times (256.52g/mole)=18.238g

Therefore, the mass of S_8 required is 18.238 grams.

7 0
3 years ago
PLEASE HELP: 60 POINTS
astra-53 [7]

Answer:

all of they above

Explanation:

7 0
3 years ago
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