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Svet_ta [14]
2 years ago
11

Please help ill give you a 100 points! Its urgent!! Q^Q

Chemistry
2 answers:
Sergio [31]2 years ago
8 0

Answer:

1. C.

Explanation:

djyliett [7]2 years ago
7 0

Answer:

?

Explanation:

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What is the relationship between the number of digits and the evolution of the tetrapod?
Nataly [62]

Answer:As the tetrapod evolved, the number of digits decreased

Explanation:

4 0
3 years ago
Read 2 more answers
How many molecules are in 3.5 moles of H2O A. 2.107x10^24 B. 3.87x10^24 C. 21.07 B. 1.72x10^23
Pani-rosa [81]

Answer:

A. 2.107x10^24

Explanation:

1 mole is defined as the particles containing in 12g of 12-C. That is 6.022x10²³ particles.

When you say 1 mole of atoms means 6.022x10²³ atoms, 1 mole of molecules means 6.022x10²³ molecules, etc.

Now, 3.5 moles of H₂O are:

3.5mol * (6.022x10²³ molecules / 1mol) = 2.107x10²⁴ molecules of H₂O.

Thus, right answer is:

<h3>A. 2.107x10^24</h3>
8 0
3 years ago
A gas exerts a pressure of 1.8 atm at a temperature of 60 degrees celsius. What is the new temperature when the pressure of the
Kamila [148]

The answer for the following problem is mentioned below.

  • <u><em>Therefore the final temperature of the gas is 740 K</em></u>

Explanation:

Given:

Initial pressure of the gas (P_{1}) = 1.8 atm

Final pressure of the gas (P_{2})  = 4 atm

Initial temperature of the gas (T_{1}) = 60°C = 60 + 273 = 333 K

To solve:

Final temperature of the gas (T_{2})

We know;

From the ideal gas equation;

we know;

P  × V = n × R × T

So;

we can tell from the above equation;

 <u>   P ∝ T</u>

(i.e.)

      <em> </em>\frac{P}{T}<em> = constant</em>

        \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1}  = initial pressure of a gas

P_{2} = final pressure of a gas

T_{1} = initial temperature of a gas

T_{2} = final temperature of a gas

        \frac{1.8}{4} = \frac{333}{T_{2} }

   T_{2} =\frac{333*4}{1.8}

    T_{2} = 740 K

<u><em>Therefore the final temperature of the gas is 740 K</em></u>

8 0
3 years ago
Periodic Table Question
natta225 [31]
Bottom left <span>on the periodic table</span>
5 0
3 years ago
A gas sample has volume 3.00 dm3 at 101
gavmur [86]

Answer:

V₂ = 21.3 dm³

Explanation:

Given data:

Initial volume of gas = 3.00 dm³

Initial pressure = 101 Kpa

Final pressure = 14.2 Kpa

Final volume = ?

Solution;

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

101 Kpa × 3.00 dm³ = 14.2 Kpa × V₂

V₂ = 303 Kpa. dm³/  14.2 Kpa

V₂ = 21.3 dm³

Explanation:

3 0
3 years ago
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