Answer:
attached below
Explanation:
Consider a torsionally elastic (GJ = 8000 lb-in2) wind tunnel model of a uniform wing, the ends of which are rigidly fastened (f
ixed) to the wind tunnel walls. The model is a symmetric airfoil with a span of 3 ft and a chord length of 6 in. The total lift-curve slope is 6 per rad. The aerodynamic center is located at the quarter-chord, and both the mass centroid and the elastic axis are at the mid-chord. (a) Calculate the divergence dynamic pressure at sea level. (b) Calculate the divergence airspeed at sea level.
2 answers:
Answer:
(a) 148.148 lb/ft^2
(b) 62.245 ft/s
Explanation:
In this question, we are asked to calculate the divergence dynamic pressure at sea level and the divergence airspeed at sea level of a torsionally elastic wind tunnel of model of uniform wing.
Please check attachment for complete step by step solution
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Answer:
a) 49.95 watts
b) The self locking condition is satisfied
Explanation:
Given data
weight of the square-thread power screw ( w ) = 100 kg = 1000 N
diameter (d) = 20 mm ,
pitch (p) = 2 mm
friction coefficient of steel parts ( f ) = 0.1
Gravity constant ( g ) = 10 N/kg
Rotation of electric power screwdrivers = 300 rpm
A ) Determine the power needed to raise to the basket board
first we have to calculate T
T = Wtan (∝ + Ф ) * ------------- equation 1
Dm = d - 0.5 ( 2) = 19mm
Tan ∝ = where L = 2*2 = 4
hence ∝ = 3.83⁰
given f = 0.1 , Tan Ф = 0.1. hence Ф = 5.71⁰
insert all the values into equation 1
T = 1.59 Nm
Determine the power needed using this equation
=
= 49.95 watts
B) checking if the self-locking condition of the power screw is satisfied
Ф > ∝ hence it is self locking condition is satisfied
Answer:
The sum of all currents entering a junction is 0
Explanation:
Current cannot disappear, so the currents leaving a junction have to equal the currents entering a junction. If you would give the currents leaving the junction an opposite sign (e.g., negative) it implies that the sum of all these currents is exactly 0.
