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Likurg_2 [28]
3 years ago
11

Consider a torsionally elastic (GJ = 8000 lb-in2) wind tunnel model of a uniform wing, the ends of which are rigidly fastened (f

ixed) to the wind tunnel walls. The model is a symmetric airfoil with a span of 3 ft and a chord length of 6 in. The total lift-curve slope is 6 per rad. The aerodynamic center is located at the quarter-chord, and both the mass centroid and the elastic axis are at the mid-chord. (a) Calculate the divergence dynamic pressure at sea level. (b) Calculate the divergence airspeed at sea level.

Engineering
2 answers:
sergejj [24]3 years ago
6 0

Answer:

(a) 148.148 lb/ft^2

(b) 62.245 ft/s

Explanation:

In this question, we are asked to calculate the divergence dynamic pressure at sea level and the divergence airspeed at sea level of a torsionally elastic wind tunnel of model of uniform wing.

Please check attachment for complete step by step solution

SVEN [57.7K]3 years ago
4 0

Answer:

Explanation:

Find attached the solution

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Answer:

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Explanation:

JavaPadGUI.java

package javapad.gui;

import java.awt.BorderLayout;

import java.awt.Container;

import java.awt.Dimension;

import java.awt.event.ActionEvent;

import java.awt.event.ActionListener;

import java.awt.event.WindowAdapter;

import java.awt.event.WindowEvent;

import java.io.File;

import java.io.FileNotFoundException;

import java.io.PrintWriter;

import java.util.Scanner;

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import javax.swing.JFrame;

import javax.swing.JLabel;

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public class JavaPadGUI extends JFrame implements ActionListener{

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  private static final String TITLE = "Macrosoft JavaPad XP";

  private static final String SLOGAN = "Macrosoft: Resistance is futile";

 

  //button names

  private static final String NEW = "New";

  private static final String LOAD = "Load";

  private static final String SAVE = "Save";

  private static final String QUIT = "Quit";

 

  private static final String FILENAME = "hardcode.txt";

  //messages

 

  private static final String QUIT_MSG = "Quitting, Save?";

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  private JTextArea txtContent;

  private JButton butNew, butLoad, butSave, butQuit;

 

  public JavaPadGUI()

  {

      super(TITLE);

      createUI();

      setSize(new Dimension(400, 300));

      setDefaultCloseOperation(EXIT_ON_CLOSE);

         

  }

 

  private void createUI()

  {

      Container c = getContentPane();

      c.setLayout(new BorderLayout(30,30));

     

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      JPanel butPanel = new JPanel();

      butPanel.add(butNew = new JButton(NEW));

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      //set command names for the buttons, these will be when button is clicked

      butNew.setActionCommand(NEW);

      butLoad.setActionCommand(LOAD);

      butSave.setActionCommand(SAVE);

      butQuit.setActionCommand(QUIT);

     

      JPanel sloganPanel = new JPanel();

      sloganPanel.add(new JLabel(SLOGAN));

     

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      JScrollPane scroll = new JScrollPane(txtContent);

     

      //now add all components

      c.add(butPanel, BorderLayout.NORTH);

      c.add(scroll, BorderLayout.CENTER);

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      butNew.addActionListener(this);

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      butSave.addActionListener(this);

      butQuit.addActionListener(this);

     

  }

  public void actionPerformed(ActionEvent e)

  {

      String cmd = e.getActionCommand();

      if(cmd.equals(NEW))

          txtContent.setText("");

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          load();

      else if(cmd.equals(SAVE))

          save();

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          quit();

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  {

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  {

      try {

          PrintWriter w = new PrintWriter(new File(FILENAME));

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      } catch (FileNotFoundException e) {

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  }

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  {

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          Scanner s = new Scanner(new File(FILENAME));

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      } catch (FileNotFoundException e) {

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RunJavaPad.java

package javapad;

import javapad.gui.JavaPadGUI;

public class RunJavaPad {

  public static void main(String[] args) {

      JavaPadGUI gui = new JavaPadGUI();

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7 0
3 years ago
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Katyanochek1 [597]

Answer: True

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