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Mashcka [7]
3 years ago
13

1. When the pneumatic device was demonstrated, explain something that was different than what you expected.

Engineering
2 answers:
Vera_Pavlovna [14]3 years ago
5 0

Answer:

1. Effect of air pressure

2. air- powered wheel chair

3. Pneumatic valves

Explanation:

1. In any pneumatic device, the mipact of air pressure to produce the moving effect on an heavy object is unexpected.

2. pneumatice demultiplexer when air in comprressed tank is allowed released to cause movement of the  chair.

3. In industries, a pneumatic valve operates by force of air when actuated. A signal causes actuation of coil. When coil is energized, compressed high pressure air is allowe to enter in a small cylinder and cause operation of valve

Alex Ar [27]3 years ago
4 0

Answer (1)

<em>The difference in the pneumatic device to what i was expecting  </em>was<em> </em>that i was expecting a device with a very complicated working system but was amazed at how simple but yet a little complex the pneumatic device was.

Answer (2)

<em>A typical device used help a disabled person </em>the pneumatic wheel chair. It uses compressed air to lift and lower the seat of the wheel chair. The compressed air is stored in a compressor below the seat and connected to the seat through piston cylinders. In order to lift, actuators activate valves that open and close at certain place to force air upward lifting the chair. Coming down is usually done by slowly leaking out the air and letting the chair descend under the weight of the user.

Answer:

<em>A pneumatic device used an automated piece of machinery </em>is the pneumatic press. The pneumatic press is a compressed air operated device in most manufacturing setting, frequently used in the automotive parts manufacturing industries. It uses compressed air to force down a ram which is usually used for baling scraps or for shaping metals.

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Mathew is manufacturing overhead transmission wires for the working of electric trains. On what does the insulation of these wir
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Answer:

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I hope this was helpful

5 0
3 years ago
For the given network, if R = 0.8 [Ω], the natural response of i in(t) is:
11111nata11111 [884]

Answer:

Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56 A

Explanation:

In physics, the determination of the term " natural response" simply means that we want to know what happens in a circuit when the value of t = 0, that is to say after the circuit has been disconnected. Hence, the value of the voltage and the current can then be determined or Calculated;

For the the natural response of i in(t) we will be using the formula below;

I(t) = Vo × t/ R = Vo/R × e^-t/h.

Where h = 1/RC = time constant.

For t= 0^- = 0.8 × 1= 0.8 V.

1/Ctotal = 1/ 2 + 1/3 = 6/5

For t = 0^+;

h =( 0.8 + 0.5) × 6/5 = 1.56 seconds.

Hence, we will have;

Vin(t) = 0.8 × e^-t/1.56.

Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56

6 0
3 years ago
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