The answer would be D: The mean and median both stay the same.
Answer:
Experimental probability of head = 2 / 5 or 40%
Step-by-step explanation:
Given:
Total chances of getting head = 20 times
Number of heads come = 8
Find:
Experimental probability of head
Computation:
Experimental probability of head = Number of heads come / Total chances of getting head
Experimental probability of head = 8 / 20
Experimental probability of head = 2 / 5 or 40%
Answer:
A. 4/15 and 0.26 repeating
Step-by-step explanation:
As we see in the long division, 4/15 is equal to 0.26666666666666666666666 (or. 0.26 repeating).
4/15
4 doesn't go into 15, so add a zero.
4.0/15
40 goes into 15 twice
40 - 30 is 10. 10 is less than 15 so add a 0.
4.00
100 goes into 15 6 times.
100 - 90 is 10. 10 is less than 15, so add a 0.
The 100 into 15 process repeats, so there's your answer.
Answer:
a. Blank time = 7:12 am
b. Blank Minutes = 30 minutes
Step-by-step explanation:
The individual got downstairs 25 minutes after 6:47am
Hence Blank time = 6:47am + 25 minutes = 7:12 am
To calculate amount of blank minutes he spent reading books
7:42am - 7:12am = 30 minutes
Answer: 0.1457
Step-by-step explanation:
Let p be the population proportion.
Given: The proportion of Americans who are afraid to fly is 0.10.
i.e. p= 0.10
Sample size : n= 1100
Sample proportion of Americans who are afraid to fly =
We assume that the population is normally distributed
Now, the probability that the sample proportion is more than 0.11:
![P(\hat{p}>0.11)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.11-0.10}{\sqrt{\dfrac{0.10(0.90)}{1100}}})\\\\=P(z>\dfrac{0.01}{0.0090453})\ \ \ [\because z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} ]\\\\=P(z>1.1055)\\\\=1-P(z\leq1.055)\\\\=1-0.8543=0.1457\ \ \ [\text{using z-table}]](https://tex.z-dn.net/?f=P%28%5Chat%7Bp%7D%3E0.11%29%3DP%28%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%3E%5Cdfrac%7B0.11-0.10%7D%7B%5Csqrt%7B%5Cdfrac%7B0.10%280.90%29%7D%7B1100%7D%7D%7D%29%5C%5C%5C%5C%3DP%28z%3E%5Cdfrac%7B0.01%7D%7B0.0090453%7D%29%5C%20%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%20%5D%5C%5C%5C%5C%3DP%28z%3E1.1055%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1.055%29%5C%5C%5C%5C%3D1-0.8543%3D0.1457%5C%20%5C%20%5C%20%5B%5Ctext%7Busing%20z-table%7D%5D)
Hence, the probability that the sample proportion is more than 0.11 = 0.1457
