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konstantin123 [22]
3 years ago
6

Three collisions are elastic and three are inelastic. Determine which collision type took place for each collision. Support your

conclusion with the data and observations from the lab.
Using your data, how are you able to determine if conservation of momentum occurs in each collision?


Write a conclusion for this lab. Also, make sure to discuss the conservation of momentum and how it applies to collisions.
Physics
1 answer:
Karolina [17]3 years ago
4 0

Answer:

Explanation:

If objects stick together, then a collision is inelastic. When objects don't stick together, If the kinetic energy is the same, then the collision is elastic.

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Explanation:

∑τ = Iα

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If the thermal energy of the system increases by 400 J, and 1,100 J of heat were added to the system, how much work did the syst
Luba_88 [7]

700 J is the work done by the system.

<u>Explanation:</u>

The first law of thermodynamics is that the change in internal energy of the system is equal to the net heat transfer to the system minus the complete work performed by the system.

                  \Delta \boldsymbol{U}=\boldsymbol{Q}-\boldsymbol{W}

Where,

∆U – Change in internal energy

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Q – Work done

Here,

<u>Given data:</u>

∆U - 400 J

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By applying the given values in the above equation, we get

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3 years ago
To test the performance of its tires, a car travels along a perfectly flat (no banking) circular track of radius 130 m. The car
marysya [2.9K]

Answer:

0.739

Explanation:

If we treat the four tire as single body then

W ( weight of the tyre ) =  mass × acceleration due to gravity (g)

the body has a tangential acceleration = dv/dt = 5.22 m/s², also the body has centripetal acceleration to the center = v² / r

where v is speed 25.6 m/s and r is the radius of the circle

centripetal acceleration = (25.6 m/s)² / 130 = 5.041 m/s²

net acceleration of the body = √ (tangential acceleration² + centripetal acceleration²) = √ (5.22² + 5.041²) = 7.2567 m/s²

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frictional force = m × net acceleration / m×g

where force of normal = weight of the body in opposite direction

coefficient of static friction = (7.2567 × m) / (9.81 × m)

coefficient of static friction = 0.739

4 0
3 years ago
Ur cool if u correctly explain how it is c
lana66690 [7]

Answer:

Explanation:

Ight

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