The weight of a ship is frequently called its "displacement" since that's the weight of the water that it uproots. It'll drift when it uproots a volume of water whose weight is break even with the weight of the ship -- this can be the buoyant drive given by the water. New water in an inland lake features a littler density than that of ocean water. Hence, a larger volume of new water is vital to supply the same weight or buoyant force. This implies the ship will ride lower in an inland lake and will ride higher within the sea.
<h3>what is buoyant force?</h3>
When an object is set in a liquid, the liquid applies an upward force we call the buoyant force. The buoyant force comes from the weight applied to the question by the liquid. Since the weight increments as the profundity increments, the weight on the foot of an object is continuously bigger than the force on the best - consequently the net upward force. The buoyant force is present whether the question coasts or sinks.
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Answer:
Time period of the osculation will be 0.0671 sec
Explanation:
It is given a vertical spring is stretched by 4 cm
So change in length of the spring x = 4 cm = 0.04 m
Mass which is hung from it m = 12 gram = 0.012 kg
Sprig force will be equal to weight of the mass
So 
k = 244.7 N/m
Now new mass is m = 28 gram = 0.028 kg
So time period with new mass will be
Rising warm air transports thermal energy by ( water vapor).
Water vapor.
Answer:
Explanation:
Gauss's Law says that the electric flux 
through a closed surface is directly proportional to the charge 
inside it. More precisely,
This means what is outside this closed surface 
does not contribute to the flux through it because field lines that go in must come out, <em>resulting a zero flux from an external charge. </em>
In our context, this means the charge 
which is outside the sphere will have zero flux through the surface; therefore, Gauss's law will only be concerned with charge 
which is inside the sphere; Hence,
Solving for gives
which is the charge inside the sphere.
Answer:
it will take him 200secs to run to the shops
(btw 200 seconds is 3minutes and 20secs)
Explanation:
distance = speed x time
time = distance / speed
1200 ÷ 6 = 200
time = 200seconds
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