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11Alexandr11 [23.1K]
2 years ago
8

the chef was careless and put the aluminum cookie sheet directly on the hot stove, which melted 0.05 kg of the aluminum. how muc

h energy did the stove supply to melt the cookie sheet?
Physics
1 answer:
sergejj [24]2 years ago
3 0

Heat required to melt 0.05 kg of aluminum is 28.7 kJ.

<h3>What is the energy required to melt 0.05 kg of aluminum?</h3>

The heat energy required to melt 0.05 kg of aluminum is obtained from the heat capacity of aluminum and the melting point of aluminum.

The formula to be used is given below:

  • Heat required = mass * heat capacity * temperature change

Assuming the aluminum sheet was at room temperature initially.;

Room temperature = 25 °C

Melting point of aluminum = 660.3 °C

Temperature difference = (660.3 - 25) = 635.3 903

Heat capacity of aluminum = 903 J/kg/903

Heat required = 0.05 * 903 * 635.3

Heat required = 28.7 kJ

In conclusion, the heat required is obtained from the heat change aluminum and the mass of the aluminum melted.

Learn more about heat capacity at: brainly.com/question/21406849

#SPJ1

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An airplane is flying in a horizontal circle at a speed of 100 m/s. The 80.0 kg pilot does not want the centripetal acceleration
Tema [17]

Answer:

The force will be "5,488". A further solution is provided below.

Explanation:

The given values are:

speed,

v = 100m/s

mass,

m = 80 kg

acceleration,

a = 7

Now,

Radius will be:

⇒ r=\frac{v^2}{ac}

⇒    =\frac{(100)^2}{7\times 9.8}

⇒    =\frac{10000}{68.6}

⇒    =145.77

Force will be:

⇒ F=m\times ac

⇒     =80\times 68.6

⇒     =5488

3 0
3 years ago
A tennis player tosses a tennis ball straight up and then catches it after 1.77 s at the same height as the point of release.
Alex_Xolod [135]

(a) The  acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.

(b) The velocity of the ball when it reaches its maximum height is zero.

(c) The initial velocity of the ball is 17.36 m/s.

(d) The maximum height it reaches is 15.36 m.

<h3>Acceleration of the ball</h3>

The acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.

<h3>Velocity of the ball at maximum height</h3>

The velocity of the ball decreases as the ball moves upwards and eventually becomes zero at maximum height.

<h3>Initial velocity of the ball</h3>

v = u - gt

at maximum height, final velocity, v = 0

0 = u - gt

u = gt

u = 9.81 x 1.77

u = 17.36 m/s

<h3>Maximum height reached by the projectile</h3>

h = ut - ¹/₂gt

h = 17.36(1.77) - ¹/₂(9.81)(1.77²)

h = 15.36 m

Thus, the  acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.

The velocity of the ball when it reaches its maximum height is zero.

The initial velocity of the ball is 17.36 m/s.

The maximum height it reaches is 15.36 m.

Learn more about maximum height here: brainly.com/question/12446886

#SPJ1

3 0
2 years ago
Condensation______.
Delicious77 [7]
Condensation d<span>rives the water cycle.</span>
7 0
3 years ago
Okay I better get a good answer for this guy I'm puttin' all my money on it.
Black_prince [1.1K]

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.

Explanation:

3 0
3 years ago
Read 2 more answers
The ballistic pendulum is a device used to measure the speed of a projectile such as a bullet. The projectile of mass m is fired
My name is Ann [436]

Answer:

Relation between initial speed of bullet and height h is given as

v = \frac{m + M}{m}\sqrt{2gh}

Explanation:

As we know that system of block and bullet swings up to height h after collision

So we have

(m + M)gh = \frac{1}{2}(m + M)v_1^2

so we have

v_1 = \sqrt{2gh}

so speed of the block + bullet just after the impact is given by above equation

Now we also know that there is no force on the system of bullet + block in the direction of motion

So we can use momentum conservation

mv = (m + M)v_1

now we have

v = \frac{m + M}{m}\sqrt{2gh}

5 0
3 years ago
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