Solution:
Let the slope of the best fit line be represented by '
'
and the slope of the worst fit line be represented by '
'
Given that:
= 1.35 m/s
= 1.29 m/s
Then the uncertainity in the slope of the line is given by the formula:
(1)
Substituting values in eqn (1), we get
= 0.03 m/s
Answer:
dear can you provide the circuit of the robot
X- points away from the charge
y- points in the direction of the force on the positive charge
z- points toward the charge
The answer for the following problem is mentioned below.
The option for the question is "A" approximately.
- <u><em>Therefore the elastic potential energy of the string is 20 J.</em></u>
Explanation:
Given:
Spring constant (k) = 240 N/m
amount of the compression (x) = 0.40 m
To calculate:
Elastic potential energy (E)
We know;
<em>According to the formula;</em>
E = 
× k × x × x
<u>E = </u><u> × k ×(x)²</u>
where;
E represents the elastic potential energy
K represents the spring constant
x represents amount of the compression in the string
So therefore,
Substituting the values in the above formula;
E = × 240 × (0.40)²
E = × 240 × 0.16
E = × 38.4
E = 19.2 J or approximately 20 J
<u><em>Therefore the elastic potential energy of the string is 20 J.</em></u>
The smaller body will have greater temperature change.
<h3><u>Explanation</u>:</h3>
Temperature is defined as the degree of hotness or coldness of a body. The relationship of the temperature with heat is described as
Q =m c dT.
Where Q is the heat content
m is the mass of body
c is the specific heat of body
dT is the temperature change of body.
Here the bodies are made up of same substance, so specific heat is same. The mass of bigger body is M and smaller body is m.
So the temperature change of the body will be dependent on the mass of the body. Heat loss by one body will be equal to heat gained by the other.
So M dT1 = mdT2.
So, M/m = dT2 / dT1.
So the the smaller body will be suffering higher temperature change.
