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2 years ago

The process of bone formation from fibers or cartilage is called

Physics

2 answers:

bekas [8.4K]2 years ago

8 0

Answer:

or known as ossification

Explanation:

frosja888 [35]2 years ago

7 0

This is called appositional growth.

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deff fn [24]

Answer:

$1- \frac{1}{2^2} = 1-\frac{1}{4} = \frac{3}{4}$

So then we will have at least 75% of the data within two deviations from the mean $\bar x \pm 2s$ .

$\bar x -2s = 98.32 -2*0.59 = 97.14$

$\bar x +2s = 98.32 +2*0.59 = 99.5$

So then the interval would be (97.14, 99.5)

Explanation:

Previous concepts

Chebyshev’s rule is appropriate for any distribution. "Chebyshev’s inequality applies to all distributions, regardless of shape". And is useful since provides a "minimum percentage of the observations that lies within k standard deviations of the mean. "

If k = 2, at least 3/4 of the measurements lie within 2 standard deviations to within the mean.

And the general formula is (1-1/k^2) represent the fraction of the data within the mean .

Solution to the problem

For this case we want to find the percentage of data that would be at least within two deviations from the mean so for this case the value of k =2 and if we replace we got:

$1- \frac{1}{2^2} = 1-\frac{1}{4} = \frac{3}{4}$

So then we will have at least 75% of the data within two deviations from the mean $\bar x \pm 2s$ .

For the other part we have the mean and deviation provided $\bar x = 98.32$ $s = 0.59$ the interval would be:

$\bar x -2s = 98.32 -2*0.59 = 97.14$

$\bar x +2s = 98.32 +2*0.59 = 99.5$

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3 years ago

An object falls a distance h from rest. If it travels 0.460h in the last 1.00 s, find (a) the time and (b) the height of its fal

nadya68 [22]

Answer:

A. Time, t = 4.35s

B. Height of its fall, S = 92.72m

Explanation:

Vo = 0 m/s

Vi = 0.46h m/s

S = h m

a = 9.81 m/s2

To calculate the time taken, we need to get the value of the distance, h.

Using the equations of motion,

Vi^2 = Vo^2 + 2aS

Where Vi = final velocity

Vo = initial velocity

a = acceleration due to gravity

S = height of its fall

(0.46h)^2 = 0 + 2*9.81*h

0.2116h^2 = 19.62h

h = 19.62/0.1648

= 92.722 m

To calculate the time,

S = Vo*t +(1/2)*a*t^2

92.772 = 0 + (1/2)*9.81*t^2

t^2 = 185.44/9.81

= 18.904

t = sqrt(18.904)

= 4.348 s

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