Answer:
The steam will start to condense at 6.6 mm into the pipe
Explanation:
The volume flow rate =π×(50/1000)²/4×10 = 0.0196 m³/s
The specific volume of the steam = 1.769 m³/kg
Therefore;
The mass flow rate = 0.0196/1.769 = 0.011099 kg/s
The resistance of the insulation material = ln(0.075/0.05)/(2×π×0.075) = 0.860 K/W
The resistance of the outside film of the insulator = 1/(15×2×π×0.075×1) = 0.14147 K/W
The total resistance = 0.14147 + 0.860 = 1.00147 K/W
1/(UA) = 1.00147 K/W
A = 2×π×0.05×1
1/U = 0.3146
U = 3.178 W/m² K
We have;
T(x) = T₀ + (Tin - T₀) exp(-UπDx/mcp)
Therefore, when T(x) = 100°C, we have;
100 = 20 + (120 - 20)exp(-3.178×π×0.05x/(0.011099 × 1.33))
Solving, we get
x = 6.597× 10⁻³ m ≈ 6.6 mm
Therefore, the steam will start to condense at 10 mm into the pipe.
Answer:
Presiune = 350 N/m²
Explanation:
Având în vedere următoarele date;
Forța = 700 N
Suprafață = 2 m²
Pentru a găsi presiunea;
Matematic, presiunea este dată de formulă;
Presiune = forță/zonă
Înlocuind în formulă, avem;
Presiune = 700/2
Presiune = 350 N/m²
Answer:
Ex(P) = -3.602 x 10^6 N/C
Explanation:
- q2 = 2.6 μC = the net charge on the conducting shell
- inner radius of conducting shell = a = 2.2 cm =0.022m
- outer radius of conducting shell = b = 4.5 cm = 0.045m
1) To get Ex(P), the value of the x-component of the electric field at point P, located a distance 8.8 cm along the x-axis from q1 ;
Ex(P) = k(q1+q2)/r^2
= 9 x 10^9 (-5.7 + 2.6) x 10^-6 /0.088^2
Ex(P) = -27.9 x 10^3/ 0.007744
Ex(P) = -3.602 x 10^6 N/C
Answer:
6000 lines/cm
Explanation:
From the question we are told that:
Grating 1=4000 lines/cm
Grating 2=6000 lines/cm
Generally The Spread of fringes is Larger when the Grating are closer to each other
Therefore
Grating 2 will spread the the light through a larger angle in the first-order pattern because its the closest with 6000 lines/cm
Answer:
<em> 30720 oscillation.</em>
Explanation:
Frequency: This can be defined as the number of oscillation completed in a seconds. The S.I unit of frequency is Hertz.
<em>From the question,</em>
<em>The frequency of the string set is 512 Hz,</em>
<em>These means that the spring set complete 512 oscillation in one seconds</em>
<em>I.e</em>
<em>if its completes in one seconds 512 oscillation.</em>
<em>Then, in one minutes, it will complete x oscillation.</em>
<em>x = 512×1min/1seconds</em>
<em>But 1 minutes = 60 seconds</em>
<em>x = 512×60/1</em>
<em>x = 30720 oscillation.</em>
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