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Viefleur [7K]
3 years ago
8

For the following equation; ____S8­ + ___ O2 à ___ SO2 a. State what type of reaction is taking place? b. Balance the equation c

. If we started with 4.0 grams of Sulfur, how many moles of Sulfur Dioxide would be produced? (You must show your work)
Chemistry
1 answer:
postnew [5]3 years ago
5 0

Answer:

a) Combustion

b) S8 + 8O2  -> 8SO2

c) 0.125 mol SO2

Explanation:

a) Combustion

b) S8 + 8O2  -> 8SO2

c)

4.0 g S8 (\frac{1 mol S8}{256 g S8})(\frac{8 mol SO2}{1 mol S8} ) =0.125 mol SO2

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4Cr(s)+3O2 (g )= Cr2O3 (s)<br> Find the theoretical yield in moles and grams
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The balanced reaction is:

<span>4Cr(s)+3O2 (g )= Cr2O3 (s)

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A food processing plant discharges 40 cfs (cubic feet per second) of process water containing an ultimate BOD (L0) of 25 mg/L an
Feliz [49]

Answer:

The right solution according to the question is provided below.

Explanation:

According to the question,

(a)

The initial conditions will be:

DO = \frac{(40\times 1.8)+(260\times 7.6)}{40+260}

      = \frac{2048}{300}

      = 6.826 \ mg/L

The initial oxygen defict will be:

Do = 8.5-6.826

     = 1.674 \ mg/L

The initial BOD will be:

Lo = \frac{(40\times 25)+(260\times 3.6)}{40+260}

    = \frac{1936}{300}

    = 6.453 \ mg/L

(b)

The time reach minimum DO:

tc = \frac{1}{(kr-kd)} ln{(\frac{0.76}{0.61} )[1-\frac{1.674(0.76-0.61)}{0.61\times 6.453} ]}

   = \frac{1}{0.15}\times ln \ 1.158

By putting the values of log, we get

   = 0.973 \ days

The distance to reach minimum DO will be:

Xc = \frac{1.1\times 3600\times 24}{5280}\times 0.973 \ days

    = 18\times 0.973

    = 17.5 \ miles

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