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almond37 [142]
3 years ago
10

Stellar fusion produces atoms up to and including ___________ Question 51 options: Helium (atomic number 2) Carbon (atomic numbe

r 6) Iron (atomic number 26) Lead (atomic number 82) Question 52 (1 point)
Chemistry
1 answer:
Ganezh [65]3 years ago
3 0
<h2>Iron (Z = 26)</h2>

Explanation:

  • Stellar fusion is the nuclear reaction that occurs in stars.
  • In this reaction, the nuclei build to form heavier elements.
  • Stars fuse elements of lighter ones to heavier ones
  • This fusion reaction occurs in their cores.
  • During this process, a lot of energy is released.
  • This process is also known as stellar nucleosynthesis as there is a synthesis of the different nucleus.
  • Stellar fusion produces lighter elements of many types including iron(Fe) and nickel(Ni) in many of the giant stars.
  • These elements remain trapped in the cores of stars.
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The final charge on each of the three separated spheres in part (b) is +3.0 μC. How many electrons would have to be added to one
marishachu [46]

Answer:

1.873\times 10^{13} electrons should be added to one of these spheres to make it electrically neutral.

Explanation:

Total charge on each sphere =  +3.0 μC =3\times 10^{-6} C

1 \mu C=10^{-6} C

In order to neutralize the positive charge equal magnitude of negative charge is to be added.

Total charge electrons, Q=  -3.0 μC =-3\times 10^{-6} C

Number of electrons = n

Charge on a single electron, e = -1.602\times 10^{-19} C

Q = n × e

-3\times 10^{-6} C=n\times (-1.602\times 10^{-19} C)

n=\frac{-3\times 10^{-6} C}{-1.602\times 10^{-19} C}=1.873\times 10^{13}

1.873\times 10^{13} electrons should be added to one of these spheres to make it electrically neutral.

4 0
3 years ago
Which of the following is true?
tresset_1 [31]

Answer:

B

Explanation:

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How does the ozone layer affect life on Earth?
zysi [14]
<span>d. filters out harmful ultraviolet radiation</span>
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? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2
Novay_Z [31]
Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
M_{dilute} = 0.50\:mol
V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







</span>
3 0
3 years ago
Which is the limiting reagent in the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? Reaction: Na2
NemiM [27]

Answer:

CuSO4

Explanation:

Na2S + CuSO4 → Na2SO4 + CuS

The reaction is balanced (same number of elements in each side)

To determine limiting reagent you need to know the moles you have of each.

Molar mass Na2S = 23 * 2 + 32 = 78

Molar mass CuSO4 = 63.5 + 32 + 16 * 4 = 159.5

Na2S mole = 15.5 / 78 = 0.2

CuSO4 mole = 12.1/159.5 = 0.076

*Remember mole = mass / MM

With that information now you have to divide each moles by its respective stoichiometric coefficient

Na2S stoichiometric coefficient : 1

Na2S : 0.2 / 1 = 0.2

CuSO4 stoichiometric coefficient: 1

CuSO4: 0.076 / 1 = 0.076

The smaller number between them its the limiting reagent, CuSO4

8 0
3 years ago
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