The ph after 17.0 ml of 0.15 m Koh has been added to 15 ml of 0.20 m hclo4 is <u>3.347</u>.
Titration is a commonplace laboratory technique of quantitative chemical analysis to determine the attention of an identified analyte. A reagent, termed the titrant or titrator, is ready as a trendy answer of recognized awareness and extent.
<u>Calculation:-</u>
Normality of acid Normality of base
= nMV nMV
= 1 × 0. 15 × 0.017 1 × 0. 20 ×0.015 L
= 2.55 × 10⁻³ = 3 × 10⁻³
The overall base will be high
net concentration = 3× 10⁻³ - 2.55 × 10⁻³
= 0.45 × 10⁻³
= 4.5× 10⁻⁴
pH = -log[4.5 × 10⁻⁴]
= 4 - log4.4
= <u>3.347</u>
A titration is defined as 'the manner of determining the amount of a substance A by using adding measured increments of substance B, the titrant, with which it reacts till precise chemical equivalence is completed the equivalence factor.
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To find the net ionic equation we must first write the balanced equation for the reaction. We must bear in mind that the reagents Ca(NO3)2 and Na2S are in the aqueous state and as product we will have CaS in the solid state, since it is not soluble in water and NaNO3 in the aqueous state.
The balanced equation of the reaction will be:
Ca(NO3)2(aq) + → Ca(aq) + 2Na(s)NO3Now, c(aq)ompounds in the aqueous state can be written in their ionic form, so the reaction will transform into:Na2S +
So, the answer will be option A
<span>Answer:
2 C8H18 + 25 O2 => 16 CO2 + 18 H2O
1.0 kg = 1000 g C8H18 = 1000 g / 114.2293 g/mole = 8.75 moles C8H18
8.75 moles C8H18 produce (16/2) (8.75) = 70 moles CO2
70 moles CO2 = (70 moles) (44.0096 g/mole) = 3081 g CO2 = 3.1 kg CO2</span>
Answer:
Option B
Covalent Bonding
Explanation:
Covalent bonds in C2H5OH are formed between the carbon and hydrogen atoms, where there are shared electron pairs.
This is a weak form of attraction that holds the C2H5OH molecule together, and can easily be broken by a polar solvent such as water.
In order for water to be able to dissolve the C2H5OH molecule, it must break the covalent bonding present in the molecule
