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3 years ago

What is the formula for carbon and chlorine

Chemistry

2 answers:

Butoxors [25]3 years ago

6 0

Carbon: C
Chlorine: Cl
Together they form carbon chloride which has the molecular formula: CCl4

Alborosie3 years ago

3 0

The chemical formula for carbon and chlorine is CCl4 (carbon tetrachloride).

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What is the instantaneous rate of formation of product C given the following information: a. Stoichiometric equation A+ B2C+ D b

quester [9]

Answer:

1.728 mol /(L*min)

Explanation:

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2 years ago

Boiling is an example of a physical property. How do the particles of gas compare to the particles as a liquid?

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2 years ago

Read 2 more answers

Air has a mass of 1.2g and a volume of 4,555ml. What is the density

coldgirl [10]

Answer:

<h2>Density = 0.00026 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3> $Density(\rho) = \frac{mass}{volume}$ </h3>

From the question

mass of air = 1.2 g

volume = 4,555 mL

Substitute the values into the above formula and solve for the density

That's

<h3> $Density = \frac{1.2}{4555}$ </h3>

= 0.0002634

We have the final answer as

<h3>Density = 0.00026 g/mL</h3>

Hope this helps you

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3 years ago

Ergosterol, a precursor of vitamin D, has δmax = 282 nm and molar absorptivity ε = 11,900 M-1cm-1. What is the concentration of

meriva

Answer:

3.6 × 10⁻⁵ M

Explanation:

Ergosterol has a maximum absorbance at λ = 282 nm. The absorbance of an analyte is related to its concentration through the Beer-Lambert's law.

A = ε × <em>l</em> × c

where,

A: absorbance

ε: molar absorptivity

<em>l</em>: optical path length

c; molar concentration

c = A / ε × <em>l </em>= 0.43 / (11,900 M⁻¹cm⁻¹) × 1.00 cm = 3.6 × 10⁻⁵ M

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2 years ago

Write empirical formula

andrew11 [14]

Answer:

$Pb(ClO_{3})_{4}\\Pb(MnO_{4})_{4}\\Fe(ClO_{3})_{3}\\\Fe(MnO_{4})_{3}\\$

Explanation:

$Pb^{4+}(ClO_{3}^{-})_{4}--->Pb(ClO_{3})_{4}\\Pb^{4+}(MnO_{4}^{-})_{4}--->Pb(MnO_{4})_{4}\\Fe^{3+}(ClO_{3}^{-})_{3}--->Fe(ClO_{3})_{3}\\\Fe^{3+}(MnO_{4}^{-})_{3}--->Fe(MnO_{4})_{3}\\$

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3 years ago