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4 years ago

What is the formula for carbon and chlorine

Chemistry

2 answers:

Butoxors [25]4 years ago

6 0

Carbon: C
Chlorine: Cl
Together they form carbon chloride which has the molecular formula: CCl4

Alborosie4 years ago

3 0

The chemical formula for carbon and chlorine is CCl4 (carbon tetrachloride).

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Aluminum oxide is an ionic substance with formula al2o3. explain what this formula means.

matrenka [14]

Answer:

the 2 means there are 2 al and the 3 means there are 3 o

Explanation:

I hope this helps

6 0

3 years ago

Write the word and balanced chemical equations for the reaction between:<br> Aluminum + iron sulfate

Art [367]

Explanation:

Aluminium - Al

Iron Sulfate - FeSO4

The reaction is given as;

Al + FeSO₄ --> Al₂ (SO₄) ₃ + Fe

The balanced equation is given as;

2 Al + 3 FeSO₄ --> Al₂ (SO₄) ₃ + 3 Fe

In words it is given as;

Aluminium + Iron Sulfate --> Aluminium Sulfate + Iron

7 0

3 years ago

Which atom has 17 protons , 18 neutrons and is 1/2 of many salts?

Ilya [14]

The answer is a chlorine atom.

4 0

3 years ago

What is the temperature of 100 liter container having 1 mole of an

Pepsi [2]

Answer:-

240.558 K

Explanation:-

Number of Moles n = 1

Pressure P = 20 kilopascals = 20 KPa

Volume V = 100 L

We know Universal Gas constant R = 8.314 L kPa K−1 mol−1

Using the relation

PV = nRT

Temperature T = P x V / ( n x R)

T = 20 KPa x 100 L / ( 1 mol x 8.314 L kPa K−1 mol−1 )

= 240.558 K

4 0

3 years ago

Help please!!!

shusha [124]

Answer:

We will collect 11.17 liters of oxygen gas.

Explanation:

$N=n\times N_A$

Where:

N = Number of particles / atoms/ molecules

n = Number of moles

$N_A=6.022\times 10^{23} mol^{-1}$ = Avogadro's number

We have:

Molecules of oxygen gas N = $3.00\times 10^{23}$

n =?

$n=\frac{N}{N_A}=\frac{3.00\times 10^{23}}{6.022\times 10^{23} mol^{-1}}$

n = 0.4982 moles of oxygen

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 1 atm (at STP)

V = Volume of gas = 10 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 273.15 K (at STP)

Putting values in above equation, we get:

$V=\frac{nRT}{P}=\frac{0.4982 mol\times 0.0821 atm L/mol K\times 273.15 K}{1 atm}$

V = 11.17 L

We will collect 11.17 liters of oxygen gas.

8 0

3 years ago