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Charra [1.4K]
3 years ago
6

Only a professional scientist can benefit from scientific knowledge. True False

Chemistry
1 answer:
svet-max [94.6K]3 years ago
4 0
The answer is False ... Anyone can benefit form <span>scientific knowledge. Thank about your Health</span>
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Is a theory testable, yes or no?
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5 0
3 years ago
Dalton law states that the partial pressure of a gas in a mixture of gases is _____ to the total pressure of the mixture.
OLEGan [10]

Answer:

Dalton law states that the partial pressure of a gas in a mixture of gases is equal to the total pressure of the mixture.

4 0
2 years ago
What's lithium scientific name?
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7 0
3 years ago
How much energy is required to raise the temperature of 10.6 grams of gaseous neon from
Alona [7]

Answer:

Approximately 1.95 \times 10^{2}\; \rm J.

Explanation:

Look up the specific heat of gaseous neon:

c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}.

Calculate the required temperature change:

\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Let m denote the mass of a sample of specific heat C. Energy required to raise the temperature of this sample by \Delta T:

Q = c \cdot m \cdot \Delta T.

For the neon gas in this question:

  • c = 1.03\; \rm J \cdot g^{-1}\cdot K^{-1}.
  • m = 10.6\; \rm g.
  • \Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Calculate the energy associated with this temperature change:

\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}.

3 0
2 years ago
To begin, follow these steps:
s344n2d4d5 [400]

Answer: 6.2  grams of the sodium acetate can dissolve in 5 milliliters of water. if 124 grams of the sodium acetate dissolves in 100 milliliters of water, then 6.2 grams of the sodium acetate can dissolve in 5 milliliters of water.

4 0
2 years ago
Read 2 more answers
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