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VMariaS [17]
3 years ago
13

In an experiment to determine if the height of a cake is determined by the temperature at which is cooked, measuring the height

of the cakes is an example of an
Chemistry
1 answer:
Bezzdna [24]3 years ago
6 0

Answer:

  • <u>Dependent variable</u>

Explanation:

In a controlled <em>experiment </em>there will be one independent variable, one dependent variable, and some controlled or constant parameters.

The target of the expermiment is to tes how the dependent variable changes with the independent variable.

So, the scientist will change (manipulate) the independent variable and measure the dependent vabiales.

Here, the temperature will be manipulated (within a range), so this is the independent variable; the height of the cake is the variable whose behavior wants to be determined, so this is the dependent variable. Controlled variables or constants may include the mixture, the size of the pan, the time of cooking, the oven, among others.

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An "empty" container is not really empty if it contains air. How may moles of nitrogen are in an "empty" two-liter cola bottle a
Lisa [10]

Answer:

1. 0.0637 moles of nitrogen.

2. The partial pressure of oxygen is 0.21 atm.  

Explanation:

1. If we assume ideal behaviour, we can use the Law of ideal gases to find the moles of nitrogen, considering that air composition is mainly nitrogen (78%), oxygen (21%) and argon (1%):  

V_{N_2}=V_{T}\times 0.78=2L \times 0.78 =1.56 L\\PV=nRT\\n_{N_2}=\frac{PV}{RT}=\frac{1 atm\times 1.56 L}{0.0821\frac{atmL}{molK}\times 298 K}\\n_{N_2}= 0.0637 mol

2. Now, in order to find he partial pressure of oxygen we need to find the total moles of air, and then the moles of oxygen. Then, we use these results to determine the molar fraction of oxygen, to multiply it with total pressure and get the partial pressure of oxygen as follows:

n_{total}=\frac{1 atm \times 2L}{0.0821 \frac{atmL}{molK}298K}=0.0817 mol

V_{O_2}=2L \times 0.21 = 0.42 L\\n_{O_2}=\frac {1atm \times 0.42 L}{0.0821 \frac{atm L}{mol K}298 K}=0.0172 mol\\X_{O_2}=\frac{n_{O_2}}{n_{total}}=\frac{0.0172 mol}{0.0817 mol}= 0.21

P_{O_2}=X_{O_2} \times P = 1 atm \times 0.21 = 0.21 atm

As you see, the molar fraction and volume fraction are the same because of the assumption of ideal behaviour.  

3 0
3 years ago
Balance this chemical equation. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
larisa86 [58]
The first one have a nice day and good luck
8 0
3 years ago
What is the random mixing of gas molecules called?
const2013 [10]
I think it’s (D) pressure
7 0
3 years ago
Read 2 more answers
Write a nuclear equation for the alpha decay of 23892U.23892U → 0−1e + 23893Np23892U → 10n + 23792U23892U → 42He + 23490Th23892U
romanna [79]

Answer:

23892U=23490Th +42He

Explanation:

In alpha decay, the daughter nucleus is two units less than the parent in atomic number. The mass number also decreases by 4 units. The daughter is thus found two places before the parent in the periodic table.

5 0
3 years ago
A force of 20 N acts upon 5 kg block caculate the accerleration of the object
Vedmedyk [2.9K]

Answer:

\boxed{\text{4 m $\cdot$ s$^{-2}$}}

Explanation:

F = ma

a = \dfrac{F}{m} = \dfrac{\text{20 N}}{\text{5 kg}} \times \dfrac{\text{1 kg$\cdot$ m $\cdot$ s$^{-2}$}}{\text{1 N}} = \text{4 m $\cdot$ s$^{-2}$}\\\\\text{The acceleration of the object is } \boxed{\textbf{4 m $\cdot$ s$^{\mathbf{-2}}$}}

 

4 0
3 years ago
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