All categories

3 years ago

Which one of these statements would be considered a hypothesis? *

Chemistry

2 answers:

laila [671]3 years ago

5 0

Answer: If I practice 30 minutes a day on my basketball skills, then I will get better at making baskets.

Explanation:

Number 1 can't be a hypothesis because it is a personal preference and that has nothing to do with hypothesis.

Number 2 has no actual factual basis for concluding that and considering that hypothesis are scientific guesses based on information you already know, that wouldn't make sense.

Therefore number 3 makes the most sense considering the fact that the more you do anything the more of a feel you get for it

Xelga [282]3 years ago

3 0

Answer:

I guess that you are going to wear blue shoes today.

Explanation:

The other ones are proven. This one is a guess, you do not know.

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A chemist prepares a solution of sodium chloride(NaCl) by measuring out 25.4g of sodium chloride into a 100ml volumetric flask a

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Answer: 4 molL-1

Explanation:

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Predict the missing product of this equation<br><br><br>1 MgF2 + 1 Li2CO3 -> 1 ______ +2LiF

ch4aika [34]

Answer:

MgCO₃

Explanation:

From the question given above, we obtained:

MgF₂ + Li₂CO₃ —> __ + 2LiF

The missing part of the equation can be obtained by writing the ionic equation for the reaction between MgF₂ and Li₂CO₃. This is illustrated below:

MgF₂ (aq) —> Mg²⁺ + 2F¯

Li₂CO₃ (aq) —> 2Li⁺ + CO₃²¯

MgF₂ + Li₂CO₃ —>

Mg²⁺ + 2F¯ + 2Li⁺ + CO₃²¯ —> Mg²⁺CO₃²¯ + 2Li⁺F¯

MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Now, we share compare the above equation with the one given in the question above to obtain the missing part. This is illustrated below:

MgF₂ + Li₂CO₃ —> __ + 2LiF

MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Therefore, the missing part of the equation is MgCO₃

8 0

3 years ago

How many liters of 1.75 M solution could be made using 35 grams of NaCl?

dolphi86 [110]

Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)

Formula:
$M = \frac{m}{MM*V}$

Solving:
$M = \frac{m}{MM*V}$
$1.75 = \frac{35}{58.44*V}$
$1.75*58.44V = 35$
$102.27V = 35$
$V = \frac{35}{102.27}$
$\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark$

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3 years ago