Answer:
5.4 M.
Explanation:
- At complete neutralization: It is known that the no. of millimoles of acid equal that of the base.
<em>(MV)acid = (MV)NaOH</em>
M of acid = ??? M, V of acid = 35.0 mL.
M of NaOH = 3.0 M, V of NaOH = 63.0 mL.
∴ M of acid = (MV)NaOH / (V)acid = (3.0 M)(63.0 mL)/(35.0 mL) = 5.4 M.
Answer:
The value of 
is 0.02495.
Explanation:
Initial concentration of 
gas = 0.675 M
Initial concentration of 
gas = 0.973 M
Equilibrium concentration of mustard gas = 0.35 M
initially
0.675 M 0.973 M 0
At equilibrium ;
(0.675-0.35) M (0.973-2 × 0.35) M 0.35 M
The equilibrium constant is given as :
![K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BS%28CH_2CH_2Cl%29_2%5D%7D%7B%5BSCl_2%5D%5BC_2H_4%5D%5E2%7D)
The relation between and 
are :
where,
= equilibrium constant at constant pressure = ?
= equilibrium concentration constant =14.45
R = gas constant = 0.0821 L⋅atm/(K⋅mol)
T = temperature = 20.0°C =20.0 +273.15 K=293.15 K
= change in the number of moles of gas = [(1) - (1 + 2)]=-2
Now put all the given values in the above relation, we get:
The value of is 0.02495.
We use the gas law named Charle's law for the calculation of the second temperature. The law states that,
V₁T₂ = V₂T₁
Substituting the known values,
(0.456 L)(65 + 273.15) = (3.4 L)(T₁)
T₁ = 45.33 K
Let's hope she didn't watch it without me or i will never be speaking to her again :))
The choices can be found elsewhere and as follows:
<span>A.The enzyme pectinase speeds up the breakdown of pectin in fruits, producing more juice.. .
B.The enzyme pectinase enhances the taste of fruit juices, making them more popular.. .
C.The enzyme pectinase speeds up the breakdown of toxins in fruits, producing more juice.
The correct answer would be A. </span>The enzyme pectinase speeds up the breakdown of pectin in fruits, producing more juice. With this, the manufacturer company will get more volume of product from same amount of resource.
