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balu736 [363]
3 years ago
10

What do elements in the same group have?

Physics
2 answers:
Leviafan [203]3 years ago
7 0

Answer:

the same number of electron shells

Explanation:

Natalija [7]3 years ago
5 0
The same number of electron shells, the atomic number is given to each individual element, same as the atomic mass, and properties have nothing to do with groups
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Which is the best procedure to make a permanent magnet?
notka56 [123]

placing a magnetically hard material in a strong magnetic field

7 0
3 years ago
Read 2 more answers
Human reaction times are worsened by alcohol. How much further (in feet) would a drunk driver's car travel before he hits the br
sweet-ann [11.9K]

Answer:

A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes

Explanation:

Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:

2as = Vf² - Vi²

s = (Vf² - Vi²)/2a

where,  

Vf = Final Velocity of Car = 0 mi/h

Vi = Initial Velocity of Car = 50 mi/h

a = deceleration of car  

s = distance covered

Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.

So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:

s = vt

FOR SOBER DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 0.33 s

s = s₁

Therefore,

s₁ = (73.33 ft/s)(0.33 s)

s₁ = 24.2 ft

FOR DRUNK DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 1 s

s = s₂

Therefore,

s₂ = (73.33 ft/s)(1 s)

s₂ = 73.33 ft

Now, the distance traveled by drunk driver's car further than sober driver's car is given by:

ΔS = s₂ - s₁

ΔS = 73.33 ft - 24.2 ft

<u>ΔS = 49.13 ft</u>

6 0
3 years ago
Object's velocity change
marshall27 [118]

the definition of acceleration in kinematics, allows to find that the correct answer is:

     2.  speed up  ( acceleration)

The kinematics study the movement of the body, the acceleration is defined as the change of the speed by the time in the interval

             a = Δv / t

Where the bold letters indicate vectors, a is the acceleration, v the velocity and t the time

Analyzing this expression we see that for there to be a change in velocity, there must be an acceleration of the body.

Let's analyze the different claims

1. True. If it is stopped and you start to move there is an acceleration, therefore there is a change in speed, but after you are moving the acceleration becomes zero and there is no change in speed

2. True. Whenever there is acceleration there is a change in speed

3. False. Moving slowly does not change the acceleration, therefore there is no change in speed

4. True. If you are moving and you stop at this moment there is an acceleration, therefore there is a change in speed, but after being stopped the acceleration is zero and there is no change in speed

5. False. If you change the direction at the instant of change there is an acceleration but after you go in the opposite direction there is not acceleration therefore there is no change in speed.

In conclusion using the definition of acceleration in kinematics, we can find the answer the condition for a change in velocity, the correct statement is:

     2.   speed up  ( acceleration)

Learn more here:  brainly.com/question/5063616

3 0
2 years ago
You push a shopping cart for fun with a force of 60N. If the shopping cart has a mass of 12kg, what is the
posledela

Answer:

\huge\boxed{\sf a = 5 \ ms^{-2}}

Explanation:

<u>Given:</u>

Force = f = 60 N

Mass = m = 12 kg

<u>Required:</u>

Acceleration = a = ?

<u>Formula:</u>

F = ma

<u>Solution:</u>

Rearranging formula

a = F / m

a = 60 / 12

a = 5 ms⁻²

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>
4 0
3 years ago
URGENT!! <br>Question in attachment. <br>thanks ​
Roman55 [17]

Answer:9

Explanation:beacause

6 0
3 years ago
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