The correct answer is:
Atoms cannot be created or destroyed by chemical reactions.
Answer:
Explanation:
mass of box, m = 60 kg
distance, d = 6.2 m
force, P = 150 N
coefficient of kinetic friction, μk = 0.21
work done by the gravitational force, Wg = Force x distance x cos 90
Wg = 0 J
Work done by the normal force, Wn = force x distance x Cos 90
Wn = 0 J
Work done by the friction force, Wf = - μk mg d
Wf = - 0.21 x 60 x 9.8 x 6.2 = - 765.58 J
Work done by the applied force, Wp = P x d
Wp = 150 x 6.2 = 930 J
Answer: a. 17.7 KJ/Mol
b. T=210K
Explanation:
Arsine, ash3 is a highly toxic compound used in the electronics industry for the production of semiconductors. its vapor pressure is 35 torr at – 111.95°c and 253 torr at – 83.6°c. using these data calculate.
the question isnt completely originally, but we could look at the likely derivation from the questions
(a) the standard enthalpy of vaporization
using the clausius clapeyron equation
In (PT1vap / PT2vap) = delta H (vap) / R ( (1/T1) - (1/T2) )
In (35Torr/253Torr) = delta H (vap) / 8.3145 ( (1/189.55) - (1/161.2) )
Therefore, Delta H (vap) = 17.7 KJ/Mol
b. Also the boiling point
What is the normal boiling point of arsine?
At the boiling point Pvap = atmospheric pressure = 1 atm=760 torr
substitution into the equation as stated in question 1
ln(760/253)=17700/8.314(1/189.55-1/T)
T=210K
Answer:
Explanation:
Given that,
Speed of transverse wave, v₁ = 20 m/s
Tension in the string, T₁ = 6 N
Let T₂ is the tension required for a wave speed of 30 m/s on the same string. The speed of a transverse wave in a string is given by :
........(1)
T is the tension in the string
is mass per unit length
It is clear from equation (1) that :
So, the tension of 13.5 N is required for a wave speed of 30 m/s. Hence, this is the required solution.
