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2 years ago

11

Which has more inertia - a 2,750 gram object or a 2,500 gram object?

2 answers:

noname [10]2 years ago

5 0

Question:

Which has more inertia - a 2,750 gram object or a 2,500 gram object?

Answer:

2,750 has more interia..

k0ka [10]2 years ago

3 0

Answer:

a 2,750 gram object has more inertia.

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what is the name of the area around a charged object where the object can exert a force on other charged objects?

shusha [124]

Answer:

An electric field is a region around a charged object where the object's electric force is exerted on other charged objects. Electric fields get weaker the farther away they are from the charge. An electric field is invisible. You can use the field line to represent it.

Explanation:

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2 years ago

during a test crash an airbag inflates to stop a dummies forward motion. the dummies mass is 75 kg. if the net force on the dumm

den301095 [7]

Use Force=Mass x Acceleration (newtons second law states force is directly proportional to the acceleration) so you can say that the force is negative and solve for Acceleration.

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3 years ago

Read 2 more answers

How do the properties of an electromagnetic wave change as a result of increasing the period of the wave?

astra-53 [7]

Answer:

as the period decreases, the frequency and energy of the wave increase

Explanation:

Electromagnetic waves are oscillations of the electric and magnetic fields, described by maxwell's equations, the speed of the wave is called the speed of light

c = λ f

E = E cos (kx - wt)

Angular velocity is related to frequency and period.

w = 2π f = 2π / T

Let's analyze what happens when the wave period decreases, angular velocity and frequency increase.

This increase in frequency is reflected with the Planck equation in wave energy

E = h f

Therefore the wave carries more energy and can lead to stronger interactions with matter.

In summary, as the period decreases, the frequency and energy of the wave increase

4 0

3 years ago

A cable with a linear density of \mu=0.109~\text{kg/m}μ=0.109 kg/m is hung from telephone poles. The tension in the cable is 572

RUDIKE [14]

Answer:

$f=16.46 Hz$

Explanation:

The equation of the speed of a mechanical wave in terms of the tension and linear density, of the cable in our case, is given by:

$v=\sqrt{\frac{T}{\mu}}$

Where:

T is the tension of the cable (T = 572 N)
μ is the linear density of the cable (μ = 0.109 kg/m)

And we know that v = λ*f

λ is the wavelength
f is the frequency

Because a standing waves pattern is produced that has 4.5 wavelengths between the two poles and the distance between poles is 19.9 meters, the value of the wavelength is: λ = 19.9/4.5 = 4.4 m.

Therefore, the frequency will be:

$\lambda f=\sqrt{\frac{T}{\mu}}$

$f=\frac{1}{\lambda}\sqrt{\frac{T}{\mu}}$

$f=\frac{1}{4.4}\sqrt{\frac{572}{0.109}}$

$f=16.46 Hz$

I hope it helps you!

6 0

3 years ago

A commercial diffraction grating has 500 lines per mm. Part A When a student shines a 480 nm laser through this grating, how man

Mademuasel [1]

Answer:

The number of bright spot is m =4

Explanation:

From the question we are told that

The number of lines is $s = 500 \ lines / mm = 500 \ lines / 10^{-3} m$

The wavelength of the laser is $\lambda = 480 nm = 480 *10^{-9} \ m$

Now the the slit is mathematically evaluated as

$d = \frac{1}{s} = \frac{1}{500} * 10^{-3} \ m$

Generally the diffraction grating is mathematically represented as

$dsin\theta = m \lambda$

Here m is the order of fringes (bright fringes) and at maximum m $\theta = 90^o$

So

$\frac{1}{500} * sin (90) = m * (480 *10^{-3})$

=> $m = 4$

This implies that the number of bright spot is m =4

8 0

3 years ago