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Serjik [45]
3 years ago
10

Define Plateau period.

Physics
1 answer:
Amiraneli [1.4K]3 years ago
5 0
A plateau period refers to a period in life where you are kind of stuck in the middle. There is little growth or decline so you are kind of at a standstill.

please vote my answer brainliest. thanks!
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A jet airplane has a velocity of 1145 knots. A knot is 1 nautical mile (nm)/hr. A nautical
Tanya [424]

Answer:

1 m = 39.37 in = 39.37/12 ft = 3.28 ft

V = 1145 k/hr  = 1145k/hr * 6076 ft/k = 6957020 ft / hr

V = 6957020 ft/hr / 3600 s/hr = 1933 ft/sec

V = 1933 ft/sec / (3.28 ft / m) = 589 m/s

Check:

88 ft/sec = 60 mph

(1145 k/hr * 6076 ft / k) 3600 sec/hr = 1933 ft/sec = 589 m/s

1933 ft/sec / (88 ft/sec) * 60 mph = 1318 mph

Also,  1318 / 1145 = 6076 / 5280       as it should

4 0
2 years ago
The velocity of a car is 65 m/s and it’s mass is 2515 kg. What is it’s KE?
Aloiza [94]
<span>Example Problems. Kinetic Energy (KE = ½ m v2). 1) The velocity of a car is 65 m/s and its mass is 2515 kg. What is its KE? 2) If a 30 kg child were running at a rate of 9.9 m/s, what is his KE? Practice Problems. IN THIS ORDER…. Page 2: #s 6, 7, 8, 5. Potential Energy. An object can store energy as the result of its position.</span><span>
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4 0
3 years ago
Read 2 more answers
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sineoko [7]
The answer is 24N. Since the body is moving with constant velocity all the forces must balance (equal & opposite)
5 0
3 years ago
Which vector best represents the force that could act concurrently with force A to produce force B
viva [34]
Chose answer 2

cheers

8 0
3 years ago
2. A student drives 7.8-km trip to school and averages a speed of
Alekssandra [29.7K]

Answer:

<em>The total time is: t=451.22 sec</em>

<em>The average speed is: V=34.57 m/s</em>

Explanation:

<u>Average speed</u>

The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

\displaystyle V=\frac{x}{t}

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.

We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is

x=2*7,800 m=15,600 m

The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

\displaystyle t1=\frac{x1}{v1}=\frac{7,800}{32.6}=239.26\ sec

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec

The total time is:

t=239.26\ sec+211.96\ sec=451.22\ sec

\boxed{t=451.22\ sec}

The average speed is:

\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s

\boxed{\displaystyle V=34.57\ m/s}

6 0
3 years ago
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