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Wewaii [24]
3 years ago
6

What is acid sulfuric's function ?​

Chemistry
1 answer:
masya89 [10]3 years ago
3 0

Answer:

The answer is below

Explanation:

Sulfuric acid is used for various purposes, some of which include the following:

1. It is used in the production of various manufactured goods.

2. It is used in the manufacturing of chemicals

3. It is also used in the making of fertilizer

4. It is used in the refining process of petroleum products

5. It is used in the processing of metals

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What describes the change in oxidation states of the following reaction
miskamm [114]
Cu  ions  reduced to  cu  and Al  oxidized to  Al  ions  is  the  answer.  copper   ions is right hand  side  of  the  E.M.F  cell  where  reduction  take  place  and is  reduced  to  copper  metal. Al   metal is  at left hand  side  of  the  E.m.f  cell where oxidation  take  place and  is  oxidized  to  Al  ions
7 0
3 years ago
Which of the following is a correct representation of the isotope of sulfur that has 19 neutrons? sulfur-19 sulfur-35 sulfur-16
Delicious77 [7]

Answer:

sulfur-35

Explanation:

Sulfur-35 is a radioactive isotope that contains 19 neutrons.

Isotopes are represented with mass numbers. Mass number is the addition of number of proton and number of neutrons.

The number of proton in sulfur = 16

Number of neutron = 19

So, mass number = no. of protons + no. of neutrons

                              = 16 + 19

                              = 35

Hence, the correct answer is sulfur-35.

4 0
3 years ago
What energy resource can be used instead of fossil fuel
lozanna [386]
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4 0
3 years ago
15. What volume of CCI, (d = 1.6 g/cc) contain
anastassius [24]

Answer:

\boxed{\text{(3) 9.6 L}}

Explanation:

1. Moles of CCl₄

n = 6.02 \times 10^{25} \text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} = \text{100.0 mol}

2. Molar mass of CCl₄

MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol

3. Mass of CCl₄

m =\text{100.0 mol} \times \dfrac{\text{154.0 g}}{\text{1 mol}} = \text{15 400 g}

4. Volume of CCl₄

V = \text{15 400 g} \times \dfrac{\text{1 cm}^{3}}{\text{1.6 g}} = \text{9600 cm}^{3}\\\\V = \text{9600 cm}^{3} \times \dfrac{\text{1 L}}{\text{1000 cm}^{3}} = \mathbf{{9.6 L}}\\\\\text{The volume of CCl$_{4}$ is } \boxed{\textbf{9.6 L}}

4 0
3 years ago
Describe the relationship between the radius of a cation and that of the atom from which forms.
vichka [17]

The radius of the cation is much smaller than the corresponding neutral atom.(b) The radius of an anion is much larger than the corresponding neutral atom.Explanation:The size of the atom or ion is inversely proportional to the nuclear charge experienced by the electrons.(a)The size of the cation is smaller than the size of the corresponding neutral atom. This is because after removal of an electron from the highest principle energy level the nuclear charge experienced by the valence electrons increases resulting in the decrease in size.(b)The size of an anion is larger than the size of the corresponding neutral atom. In an anion, an extra electron is added to the highest principle energy level but the effective nuclear charge pulling the electrons towards the nucleus is still same. The net effective nuclear charge experienced by the electrons present in the outermost shell decrease. Moreover, due to the added electron, the repulsion between the electrons also increases resulting in the increase in size

Make since? i hope this helps

4 0
3 years ago
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