Answer:
0.0835 M
Explanation:
Step 1: Write the balanced equation
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of HCl
0.0250 L of 0.105 M HCl react.
0.0250 L × 0.105 mol/L = 2.63 × 10⁻³ mol
Step 3: Calculate the reacting moles of NaOH
The molar ratio of NaOH to HCl is 1:1. The reacting moles of NaOH are 1/1 × 2.63 × 10⁻³ mol = 2.63 × 10⁻³ mol.
Step 4: Calculate the molarity of NaOH
2.63 × 10⁻³ moles of NaOH are in 0.0315 L of solution.
M = 2.63 × 10⁻³ mol / 0.0315 L = 0.0835 M
Answer:
Oxygen, 43kg - Carbon, 16kg - Hydrogen, 7kg - Nitrogen, 1.8kg - Calcium, 1kg - Phosphorus, 0.78kg - Potassium, 0.14kg - Sulfur, 0.14kg - Sodium, 0.10kg - Chlorine, 0.095kg - and Magnesium, 0.019kg.
Explanation:
0.00208 is the correct standard form
Answer:
Please find the attachment to this question:
Explanation:
By eliminating the agent produced in the reaction, it will give a structure of the alkene. please find the given attachment.
