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2 years ago

Which of the following processes are physical changes? Mark all

Chemistry

1 answer:

stich3 [128]2 years ago

7 0

The process that is physical changes is:

mixing frozen orange juice concentrate with water

<h3>What is a physical change?</h3>

A physical change can be described as a type of change that take place in physical without chemical reaction as opposed to chemical change.

They are changes that are usually reversible it should be noted that physical change do not involve the alterations as regards the chemical make up of a particular substance and as a result of this , in physical change, there is no formation of new product.

Therefore, The process that is physical changes is mixing frozen orange juice concentrate with water

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Be sure to answer all parts. what are the concentrations of hso4−, so42−, and h in a 0. 31 m khso4 solution? (hint: h2so4 is a s

disa [49]

At equilibrium the concentrations of:

[HSO₄⁻] = 0.10 M;

[SO₄²⁻] = 0.037 M;

[H⁺] = 0.037 M;

There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.

HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid. HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.

R $HSO_4^-$ ⇄ $H^+ + SO_4^2^-$

I $0.14$

C $- x$ $+x$ $+x$

E $0.14-x$ $x$ $x$

$K_a = 1.3$ × $10^-^2$ for $HSO^-_4$ . As a result,

$\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a$

$K_a$ is large. It is no longer valid to approximate that $[HSO^-_4]$ at equilibrium is the same as its initial value.

$\frac{x^2}{0.14-y} = 1.3 * 10^-^2$

$x^2+1.3*10^-^2x - 0.14$ × $1.3$ × $10^-^2= 0$

Solving the quadratic equation for $x , x \geq 0$ since $x$ represents a concentration;

$x=0.0366538$

Then, round the results to 2 significant figure;

$[SO_4^2^-] = x = 0.037 mol. L ^-^1$
$[H^+] = x = 0.037 mol. L ^-^1$
$[HSO_4^-] = 0.14 - x = 0.10 mol. L ^-^1$

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2 years ago

ACTUAL YIELD VS THEORETICAL YIELD?

lawyer [7]

Actual yield over theoretical yield, then multiply by 100

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3 years ago

A student wants to reclaim the iron from an 18.0-gram sample of iron(III) oxide, which

lilavasa [31]

Answer:

$m_{Fe}=12.6gFe$

Explanation:

Hello,

In this case, since we have grams of iron (III) oxide whose molar mass is 159.69 g/mol are able to compute the produced grams of iron by using its atomic mass that is 55.845 g/mol and their 2:4 molar ratio in the chemical reaction:

$m_{Fe}=18.0gFe_2O_3*\frac{1molFe_2O_3}{159.69gFe_2O_3}*\frac{4molFe_2O_3}{2molFe_2O_3} *\frac{55.845gFe}{1molFe_2O_3} \\\\m_{Fe}=12.6gFe$

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3 years ago

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Vika [28.1K]

D IS THE ANSWER TO YOUR QUESTION

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3 years ago

E85 fuel is a mixture of 85% ethanol and 15% gasoline by volume. What mass in kilograms of E85 (d = 0.758 g/mL) can be contained

alexandr402 [8]

The answer is: mass is 40.17 kilograms.

d = 0.758 g/mL; density of fuel.

V = 14.0 gal; volume.

A gallon is a unit of volume in both the US customary and imperial systems of measurement. The US gallon is defined as 231 cubic inches (3.785 liters).

1 gal = 3785.41 mL.

V = 14 gal · 3785.41 mL:

V = 52995.74 mL.

m = 52995.74 mL · 0.758 g/mL.

m = 40170.77 g; mass of fuel.

m = 40170.77 g ÷ 1000 g/kg.

m = 40.17 kg.

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3 years ago

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