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IgorC [24]
3 years ago
7

jet is flying at 500 mph east relative to the ground. A Cessna is flying at 150 mph 60° north of west relative to the ground. Wh

at is the Cessna's speed relative to the 747? A 634 mph B 578 mph C 590 mph D 444 mph E 610 mph

Physics
1 answer:
Greeley [361]3 years ago
8 0

Answer:

C. 590 mph

\vert v_{cj}\vert=589.49\ mph

Explanation:

Given:

  • velocity of jet, v_j=500\ mph
  • direction of velocity of jet, east relative to the ground
  • velocity of Cessna, v_c=150\ mph
  • direction of velocity of Cessna, 60° north of west

Taking the x-axis alignment towards east and hence we have the velocity vector of the jet as reference.

Refer the attached schematic.

So,

\vec v_j=500\ \hat i\ mph

&

\vec v_c=150\times (\cos120\ \hat i+\sin120\ \hat j)

\vec v_c=-75\ \hat i+75\sqrt{3}\ \hat j\ mph

Now the vector of relative velocity of Cessna with respect to jet:

\vec v_{cj}=\vec v_j-\vec v_c

\vec v_{cj}=500\ \hat i-(-75\ \hat i+75\sqrt{3}\ \hat j )

\vec v_{cj}=575\ \hat i-75\sqrt{3}\ \hat j\ mph

Now the magnitude of this velocity:

\vert v_{cj}\vert=\sqrt{(575)^2+(75\sqrt{3} )^2}

\vert v_{cj}\vert=589.49\ mph is the relative velocity of Cessna with respect to the jet.

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A researcher reports an f-ratio with df = 3, 36 for an independent-measures experiment. how many treatment conditions were compa
user100 [1]

The correct option is B.

There were 4 treatment conditions compared in the experiment.

F ratio plays an essential role in performing a particular dataset of ANOVA. F ratio is particularly a ratio which is obtained by the between-group variance or it is also called MSB and also within-group variance known as MSW. Any  F-ratio which is computed is compared with the critical F-ratios from the table as it will check out if there are any variations available between the groups or not.

The researcher reports an F-ratio where the degrees of freedom = 3, 36.

F-ratio is obtained by the calculation of dividing the Mean squared errors because of the treatment by the Mean squared error which occurs due to error.

For the particular case, the researcher reports an F-ratio having degrees of freedom = 3, 36. It is indicating that the treatments are being distributed with degrees of freedom which is 3 and specified errors are distributed with degrees of freedom which is 36.

Let the treatments which were involved in the study can be denoted by k.

Let the total number of individuals involved in the study can be taken as N.

Then, the  treatments will be having  degrees of freedom as,

df_{treatments} = k-1

3=k-1

k=3+1=4

Therefore, the required treatment condition number that was compared is 4.

Learn to know more about degrees of freedom on

brainly.com/question/28527491

#SPJ4

6 0
1 year ago
The drawing shows a hydraulic chamber with a spring (spring constant = 1600 N/m) attached to the input piston and a rock of mass
Triss [41]

Answer:

\Delta x=245\ mm

Explanation:

Given:

  • spring constant of the spring attached to the input piston, k=1600\ N.m^{-1}
  • mass subjected to the output plunger, m=40\ kg

<u>Now, the force due to the mass:</u>

F=m.g

F=40\times 9.8

F=392\ N

<u>Compression in Spring:</u>

\Delta x=\frac{F}{k}

\Delta x=\frac{392}{1600}

\Delta x=0.245\ m

or

\Delta x=245\ mm

8 0
4 years ago
A wildlife researcher is tracking a flock of geese. The geese fly 4.0km due west, then turn toward the north by 40 degrees and f
BaLLatris [955]

Answer:

(a). The distance from the initial position is 6.68 km.

(b).  The magnitude of their displacement is 7.05 km.

Explanation:

Given that,

Geese fly 4.0 km due west, then turn to north by 40° and fly another 3.5 km.

(a). We need to calculate the distance from the initial position

Using formula of distance

D=AB+BC\cos\theta

Put the value into the formula

D=4.0+3.5\cos40

D=6.68\ km

(b). We need to calculate the magnitude of their displacement

Using formula of displacement

AC=\sqrt{CD^2+AD^2}

AC=\sqrt{(3.5\sin40)^2+(6.68)^2}

AC=7.05\ Km

Hence, (a). The distance from the initial position is 6.68 km.

(b).  The magnitude of their displacement is 7.05 km.

8 0
3 years ago
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A particle of ink in a ink-jet printer carries a charge of -8x 10^-13 C and is deflected onto paper force of 3.2x10^-4. Find the
vitfil [10]
Beef and cheddar is your answer
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3 years ago
. In science, which of the following is NOT true about scientific theories a. They are generated by the testing of many hypothes
nydimaria [60]

Answer:

The correct option is  b) By the time they get to be theories, they cannot be disproven. It's not necessary that the theories are always right. They can be proven wrong.

Explanation:

5 0
4 years ago
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