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Mariulka [41]
2 years ago
5

Which term best describes those processes that move weathered rock materials and soils downslope?

Physics
1 answer:
mote1985 [20]2 years ago
5 0

Answer:

mass wasting

Explanation:

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Batman, whose mass is 89.5 kg, is holding on to the free end of a 13.4 m rope, the other end of which is fixed to a tree limb ab
astra-53 [7]

Answer:

8.2\times 10^{3} J

Explanation:

L = length of the rope connected = 13.4 m

\theta = Angle made by the rope with the vertical = 72.4°

h = height gained by the batman above the reference point  

Height gained by the batman above the reference point  is given as

h = L(1 - Cos\theta )

m = mass of batman = 89.5 kg

g = acceleration due to gravity = 9.8 ms⁻²

Work done against gravity is same as the gravitational potential energy gained by batman and is given as

W = mgh

W = mgL(1 - Cos\theta )

Inserting the above values

W = (89.5)(9.8)(13.4)(1 - Cos72.4 )

W = 8.2\times 10^{3} J

3 0
3 years ago
How much heat is required to raise the temperature of 0.25 kg of water from 20°C to 30°C
pentagon [3]

Answer:

10500 J/kg/*C

Explanation:

Quantity of heat required=mass of substance x specific heat capacity x change in temperature

Quantity of heat required=0.25 x 4200 x [30-20]

Quantity of heat required=0.25 x 4200 x 10

Quantity of heat required=10500 J/kg/*C

3 0
3 years ago
How much of the universe do scientists speculate is composed of dark energy
algol [13]

Answer: Approximately 65% from what i have learnt.

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3 years ago
How is urine produced
Tom [10]

Urine is a liquid by-product of metabolism in humans and in many other animals. Urine flows from the kidneys through the ureters to the urinary bladder. Urination results in urine being excreted from the body through the urethra.  

5 0
3 years ago
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Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. If the surface charg
bekas [8.4K]

Answer:

5.3\times 10^3 N/C

Explanation:

We are given that

Distance between plates=d=2.2 cm=2.2\times 10^{-2} m

1 cm=10^{-2} m

\sigma=47nC/m^2=47\times 10^{-9}C/m^2

Using 1 nC=10^{-9} C

We have to find the magnitude of E in the region between the plates.

We know that the electric field for parallel plates

E=\frac{\sigma}{2\epsilon_0}

E_1=\frac{\sigma}{2\epsilon_0}

E_2=\frac{\sigma}{2\epsilon_0}

E=E_1+E_2

E=\frac{\sigma}{2\epsilon_0}+\frac{\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}

Where \epsilon_0=8.85\times 10^{-12}C^2/Nm^2

Substitute the values

E=\frac{47\times 10^{-9}}{8.85\times 10^{-12}}

E=5.3\times 10^3 N/C

Hence, the magnitude of E in the region between the plates=5.3\times 10^3 N/C

5 0
3 years ago
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