The correct answer is D. learn to do a task independently.
The near-point distance of the eye is 11 cm.
<h3>What is the eye's near-point distance?</h3>
The near-point distance of the eye is the closest possible distance an object can be from the eye in order for its image to be formed on the retina. It can also be termed the closest distance of accommodation.
The near-point distance of the eye in the given scenario can be calculated using the lens formula given below:
1/f = 1/v + 1/u
where;
f = focal length
v = image distance
u = object distance
From the data provided;
f = 2.20 cm
v = 2.75 cm
u = ?
Solving for u:
1/u = 1/f - 1/v
1/u = 1/2.20 - 1/2.75
1/u = 0.91
u = 11 cm
In conclusion, the lens formula is used to determine the eye's near-point distance.
Learn more about eye's near-point distance at: brainly.com/question/16391605
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Answer:
Equal
Explanation:
The impulse theorem states that the impulse exerted on each cart is equal to the change in momentum of the cart:
where
I is the impulse
pf is the final momentum
pi is the initial momentum
The impulse is equal to the product between the force applied and the contact time:
In this case, the force applied to the two carts (F) is the same, and the contact time (
) is the same as well. Therefore, the impulse exerted on the two carts is the same.
Moreover, the initial momentum of the two carts is also the same (zero, because they start from rest: 
). So the formula becomes
And since I is the same for the two carts, the final momentum (
) will also be equal.
It’s ultrasonic 100% not much help but I knew the answer
