Question

Kaylib’s eye-level height is 48 ft above sea level, and Addison’s eye-level height is 85 1/3 ft above sea level. How much farther can Addison see to the horizon? Use the formula d=sq-rt(3h)/(2), with d being the distance they can see in miles and h being their eye-level height in feet.
a.sq-r 2 mi
b.2 sq-r 2 mi
c.14 sq-r
d 28sq-r2

Answer 1

The distance they can see: d = √ ( 3 h / 2 )
d ( Addison ) = √ ( 3 · 256/3 / 2 ) = √ 124 = √ 64 · 2 = 8 √ 2d ( Kaylib ) = √ ( 3 · 48 / 2 ) = √ 72 = √ 36 · 2 = 6 √ 2d ( Addison ) - d ( Kaylib ) = 8 √ 2 - 6 √ 2 = 2 √ 2Answer:  b.  2 √ 2 mi.