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allsm [11]
3 years ago
6

Is the meter, centimeter, or millimeter more useful for measuring the length and width of your classroom? why?

Physics
1 answer:
Verizon [17]3 years ago
8 0
A meter because centimeters and millimeters are way smaller than meters
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You walk 100m due north. You then turn and walk 55m due east. You then make another turn and walk 12m due south. What is the res
lord [1]

Answer:

Explanation:

Important here is to know that due north is a 90 degree angle, due east is a 0 degree angle, and due south is a 270 degree angle. Then we find the x and y components of each part of this journey using the sin and cos of the angles multiplied by each magnitude:

A_x=100cos90\\A_x=0\\B_x=55cos0\\B_x=55\\C_x=12cos270\\C_x=55

Add them all together to get the x component of the resultant vector, V:

V_x=55

Do the same to find the y components of the part of this journey:

A_y=100sin90\\A_y=100\\B_y=55sin0\\B_y=0\\C_y=12sin270\\C_y=-12

Add them together to get the y component of the resultant vector, V:

V_y=88

One thing of import to note is that both of these components are positive, so the resultant angle lies in QI.

We find the final magnitude:

V_{mag}=\sqrt{55^2+88^2} and, rounding to 2 sig dig's as needed:

V_{mag}= 1.0 × 10² m; now for the direction:

\theta=tan^{-1}(\frac{88}{55})= 58°

7 0
3 years ago
Describe what a reactant is
ohaa [14]

Answer:

the element that takes part in a chemical reactions

there are usually two or more reactants in chemical reactions

except decomposition reactions

4 0
3 years ago
Read 2 more answers
2. If 66.2 J of thermal energy is removed from a 0.141 kg piece of iron, what is its change in temperature? The specific heat ca
yawa3891 [41]

Answer: I think is -5

Explanation:

3 0
3 years ago
A circular loop of wire has radius of 9.50 cmcm. A sinusoidal electromagnetic plane wave traveling in air passes through the loo
m_a_m_a [10]

Answer:

The induced emf  is  \epsilon  = 0.1041 \  V  

Explanation:

From the question we are told that

   The  radius of the circular loop is  r =  9.50 \ cm  =  0.095 \ m

     The  intensity of the wave is  I  =  0.0215 \ W/m^2

      The wavelength is  \lambda =  6.90\ m

Generally the intensity is mathematically represented as

         I  =  \frac{ c *  B^2  }{ 2 * \mu_o  }

Here  \mu_o is the permeability of free space with value  

         \mu_o  =  4 \pi *10^{-7} N/A^2

B is the magnetic field which can be mathematically represented from the equation as

          B  =  \sqrt{ \frac{ 2 *  \mu_o  *  I  }{ c} }

substituting values

          B  =  \sqrt{ \frac{ 2 *  4\pi *10^{-7} *   0.0215  }{ 3.0*10^{8}} }

          B  =  1.342 *10^{-8} \  T

The  area is mathematically represented as

       A =  \pi r^2

substituting values

       A =  3.142 *   (0.095)^2

       A = 0.0284

The angular velocity is mathematically represented as

        w =  2 *  \pi  *  \frac{c}{\lambda }

substituting values          

       w =  2 *  3.142   *  \frac{3.0*10^{8}}{ 6.90 }  

        w =  2.732 *10^{8} rad  \ s^{-1}  

Generally the induced emf is mathematically represented as

        \epsilon  =  N *  B  *  A  *  w * sin (wt )

At maximum induced emf  sin (wt)  =  1

    So

         \epsilon  =  N *  B  *  A  *  w

substituting values

         \epsilon  = 1  *    1.342 *10^{-8}   *  0.0284  *2.732 *10^{8}  

         \epsilon  = 0.1041 \  V  

         

7 0
3 years ago
Which best describes the electric field created by a positive charge?
Vlad [161]
Its rays point away from the charge
3 0
3 years ago
Read 2 more answers
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